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3 years ago

Which best explains why blood is considered to be a suspension?

1 answer:

5 0

I think the best answer is b): it contains particles that can settle out.

The definition of suspension is a heterogeneous (that is same in all parts) mixture that contains particles that could undergo sedimentation (settle down) - this definition is close to b). It should not matter whether those particles are nutrients( so A or C are not good answers).

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1.what happens in the nucleus of an atom when an alpha particle is emitted?

coldgirl [10]

1) The nucleus of an atom loses 2 protons and 4 neutrons.
2) The nucleus of an atom gains a proton and it's neutrons remain the same.

7 0

3 years ago

Read 2 more answers

AnnZ [28]

The answer is B. (solid)

4 0

3 years ago

Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution

uysha [10]

Answer: The volume of the new solution is 83.33 mL.

Explanation:

Given: $V_{1}$ = 200 mL, $M_{1}$ = 0.5 M

$V_{2}$ = ?, $M_{2}$ = 1.2 M

Formula used to calculate the volume of new solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 200 mL = 1.2 M \times V_{2}\\V_{2} = 83.33 mL$

Thus, we can conclude that volume of the new solution is 83.33 mL.

5 0

3 years ago

What is the difference between a strong acid and a concentrated acid?

storchak [24]

A concentrated acid has a relatively large amount of solute dissolved in the solvent. A dilute acid has a relatively smaller amount of solute dissolved in the solvent. In a solution of a strong acid there would be solvated ions present, but no associated molecules present.

3 0

3 years ago

If a sample contains 70.0 % of the R enantiomer and 30.0 % of the S enantiomer, what is the enantiomeric excess of the mixture?

NeTakaya

Answer:

the enantiomeric excess of the mixture is 40%

Explanation:

The computation of the enantiomeric excess of the mixture is shown below:

As we know that

$= |\frac{R - S}{R + S} |\times 100\\\\= |\frac{70 - 30}{70 + 30}| \times 100\\\\= 40\%$

Hence, the enantiomeric excess of the mixture is 40%

3 0

3 years ago