Answer:

Explanation:
Hello!
In this case, since the undergoing chemical reaction is:

We first need to identify the limiting reactant given the masses of nitrogen and hydrogen:

It means that only 0.647 moles of ammonia are yielded, so the resulting enthalpy change is:

Best regards!
Answer: 136 g of
must be reacted to inflate an air bag to 70.6 L at STP.
Explanation:
Using ideal gas equation:
P= pressure of nitrogen gas = 1 atm (at STP)
V =volume of nitrogen gas = 70.6 L
n = number of moles of nitrogen gas = 1 atm (at STP)
R = gas constant = 0.0821 Latm/Kmol
T = temperature of nitrogen gas = 273 K (at STP)
For the balanced chemical reaction:

3 moles of nitrogen are produced by = 2 moles of 
3.14 moles of nitrogen are produced by =
moles of 
Mass of
= Moles × Molar mass = 2.09 mole × 65 g/mol = 136 g
That it is number 17 35.45 it's period is 3.
Hope that helped ^^