Answer:
Bears
Explanation:
because starch is heavy and it requires a lot of oxygen in an environment. so having starch in an environment with less oxygen could probably cause fatigue
The temperature is held constant at (b) and (d). At these points, the substance is changing states. B is changing from solid to liquid and D is changing from liquid to gas
Answer:
Explanation:
<em>First calculate how many moles of O2 you have. O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters.</em>
<em>1.5625 × 22.4 = 35 liters.</em>
<em>Its been 15 years since I graduated HS, and I still remember how to do this. Do your own homework next time and in 15 years you may be able to do the same.</em>
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<em>AND</em><em> </em><em>PLEASE</em><em> </em><em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>"</em><em>BRAINLIEST</em><em>"</em><em> </em><em>ANSWER</em><em> </em>
<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em> </em><em>YOU</em>
<u>Answer:</u> The concentration of
ions is 0.10 M and that of
ions is 0.30 M
<u>Explanation:</u>
We are given:
Concentration of
= 0.10 M
The chemical equation for the ionization of aluminium bromide follows:

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions
So, concentration of aluminium ions = 0.10 M
Concentration of bromide ions = ![[(3\times 0.1)]=0.3M](https://tex.z-dn.net/?f=%5B%283%5Ctimes%200.1%29%5D%3D0.3M)
Hence, the concentration of
ions is 0.10 M and that of
ions is 0.30 M
Answer:
Adenosine triphosphate is a complex organic chemical that provides energy to drive many processes in living cells, e.g. muscle contraction, nerve impulse propagation, and chemical synthesis. Found in all forms of life, ATP is often referred to as the "molecular unit of currency" of intracellular energy transfer. Wikipedia
Formula: C10H16N5O13P3
Molar mass: 507.18 g/mol
IUPAC ID: [[(2R,3S,4R,5R)-5-(6-aminopurin-9-yl)-3,4-dihydroxyoxolan-2-yl]methoxy-hydroxyphosphoryl] phosphono hydrogen phosphate
Acidity (pKa): 6.5
Soluble in: Water
UV-vis (λmax): 259 nm
Explanation: