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Amiraneli [1.4K]
3 years ago
7

Two soccer teams, the Bears and the Panthers, played games at the same time in two different locations. The Bears game was playe

d at sea level, where there is a normal amount of oxygen. Before their game, the players on the Bears ate a lunch of mostly starch. The Panthers game was played at very high altitude, where there is less oxygen. The players on the Panthers ate a lunch of starch and protein. Which team probably did better in their game?
1 point
Chemistry
1 answer:
motikmotik3 years ago
5 0

Answer:

Bears

Explanation:

because starch is heavy and it requires a lot of oxygen in an environment. so having starch in an environment with less oxygen could probably cause fatigue

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Vilka [71]

Answer:

Explanation:

CH₃COOH + NaOH = CH₃COONa + H₂O .

42.5 mL of .115 M of NaOH will contain .0425 x .115 moles of NaOH

= 48.875 x 10⁻⁴ moles NaOH

It will react with same number of moles of acetic acid

So number of moles of acetic acid in 3.45 mL = 48.875 x 10⁻⁴

number of moles of acetic acid in 1000 mL = 48.875 x 10⁻⁴ x 10³ / 3.45 moles

= 1.4167 moles

= 1.4167 x 60 gram

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8 0
3 years ago
Which of the following species contains manganese with the highest oxidation number?
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In NaMnO₄, Mn has the highest oxidation number.

The question is incomplete, the complete question is;

Which of the following species contains manganese with the highest oxidation number?

A) Mn

B) MnF₂

C) Mn₃(PO₄)₂

D) MnCl₄

E) NaMnO₄

In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.

1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.

2) For MnF₂;

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3) For Mn₃(PO₄)₂

Mn has an oxidation number of +2

4) For MnCl₄

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Learn more: brainly.com/question/10079361

7 0
3 years ago
Calculate the molecular weight when a gas at 25.0 ∘C and 752 mmHg has a density of 1.053 g/L . Express your answer using three s
stiks02 [169]

Answer:

26.0 g/mol is the molar mass of the gas

Explanation:

We have to combine density data with the Ideal Gases Law equation to solve this:

P . V = n . R .T

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760 mmHg ____ 1 atm

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Moles = Mass / molar mass.

We can replace density data as this in the equation:

0.989 atm . 1L = (1.053 g / x ) . 0.082 L.atm/mol.K . 298K

(0.989 atm . 1L) / (0.082 L.atm/mol.K . 298K) = 1.053 g / x

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