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Ede4ka [16]
3 years ago
9

3h = 7(\frac{2}{7} -\frac{3}{7}h)-10" alt="3h = 7(\frac{2}{7} -\frac{3}{7}h)-10" align="absmiddle" class="latex-formula">
I've been able to simplify it a good deal but can't figure out how to solve it in the end,... 17 points to you,... thanks,...!

3h = 7(\frac{2}{7} -\frac{3}{7}h)-10\\
Parenthesis Simplification
3h = 2 -3h-10\\
Re-write equation
3h = 2-10-3h\\
Subtract
3h = -8-3h\\
Add 3h to both sides of the equation to take away the "- 3h"
3h+3h = -8-3h+3h
Simplify
6h = -8\\
Divide?
3h = -4\\
Then what?

Thanks for the help,... please answer in full explanation,... Chow!
Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Your method is correct.

Now,

\implies 3h = -4

Divide both sides with 3

3h \div 3 = -4 \div 3

h = -1.333...

cluponka [151]3 years ago
3 0

h = -4/3 just transfer the 3 into denominator it will be the simplest answer.

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4 0
3 years ago
PLEASE HELP!!
Vikentia [17]

Answer:

Part a) The inequality that represent the situation is

x+(3x)+(6x) \leq 350\ in  

Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to 35\ inches

Step-by-step explanation:

Let

x------> the length of the first wire

3x---> the length of the second wire

2(3x)=6x -----> the length of the third wire

Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION

we know that

The inequality that represent the situation is

x+(3x)+(6x) \leq 350

Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?

we know that

The shortest piece of wire is the first wire

so

Solve the inequality

x+(3x)+(6x) \leq 350

10x \leq 350

Divide by 10 both sides

x \leq 35\ in

The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to 35\ inches

4 0
2 years ago
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