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RideAnS [48]
3 years ago
8

Find the area of trapezium whose parallel side are 10 and 12 cm. And height is 7 cm

Mathematics
2 answers:
ozzi3 years ago
5 0
<h2><u>Given</u> :</h2>

Length of parallel sides = 10 cm and 12 cm

Height = 7 cm

<h2><u>What </u><u>To</u><u> Find</u> :</h2>

Area of trapezium

<h2><u>Formula</u><u> Using</u> :</h2>

\begin{gathered} {\underline{\boxed{ \rm {\red{Area  \: of \:  trapezium \:  =  \:  \frac{1}{2} \:  \times  \: (a \:  +  \: b) \:  \times  \:Height }}}}}\end{gathered}

Where ,

  • a and b is Parallel sides

<h2><u>Solution</u> :</h2>

\begin{cases}  \large\bf\purple{ \implies} \rm \:Area  \: of \:  trapezium \:  =  \:  \frac{1}{2} \:  \times  \: (10 \:  +  \: 12) \:  \times  \:7 \\  \\  \large\bf\purple{ \implies} \rm \:Area  \: of \:  trapezium \:  =  \:  \frac{1}{2} \:  \times  \: 22\:  \times  \:7 \\  \\  \large\bf\purple{ \implies} \rm \:Area  \: of \:  trapezium \:  =  \:  \frac{1}{ \cancel2} \:  \times   \:  \cancel{22} \:  ^{11} \:  \times  \:7 \\  \\ \large\bf\purple{ \implies} \rm \:Area  \: of \:  trapezium \:  =  \:11 \:  \times  \: 7 \\  \\ \large\bf\purple{ \implies} \rm \:Area  \: of \:  trapezium \:  =  \:77 \:  {cm}^{2}  \end{cases}

<h2 /><h2 />

kompoz [17]3 years ago
4 0

Answer:

77 cm²

Step-by-step explanation:

We know that

Area of trapezium = ½ (a + b) × h

Area = ½ × (10 + 12) × 7

Area = ½ × 22 × 7

Area = 11 × 7

Area = 77 cm²

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This question is impossible to solve.

this is why:

if 4x-4=0
then x=1

so if 8x + 4 = 8

then x is false.

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2 years ago
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A faucet in a large tank can fill the tank in 12 hours. However, there is a hose in the tank which would be able to empty the ta
Kruka [31]
It would take the faucet 18 hours to fill the tank because 18/12=1.5.  That means it will be 1.5 times slower to fill the tank up with the hose on.  1.5*12=18.
7 0
3 years ago
Solve the system of equations. 5x y = 9 3x 2y = 4 (−2, 5) (1, 4) (2, −1) (4, −4)
kobusy [5.1K]

The solution of the system of equations that is given is (2,-1).

Given a system of equations are 5x+y=9 and 3x+2y=4.

A system of linear equations (or linear system) is a collection of one or more linear equations involving the same variables.  A solution to a linear system is an assignment of values to the variables such that all the equations are simultaneously satisfied.

The given equations are

5x+y=9    ......(1)

3x+2y=4  ......(2)

Here, the substitution method is used to solve the system of equations.

Find the value of y from equation (1) by subtracting 5x from both sides.

5x+y-5x=9-5x

y=9-5x

To find the value of x substitute the value of y in equation (2).

3x+2(9-5x)=4

Apply the distributive property a(b+c)=ab+ac as

3x+2×9-2×5x=4

3x+18-10x=4

Combine the like terms on the left side as

-7x+18=4

Subtract 18 from both sides and get

-7x+18-18=4-18

-7x=-14

Divide both sides by -7 and get

(-7x)÷(-7)=(-14)÷(-7)

x=2

Substitute the value of x in equation (1) and get

5(2)+y=9

10+y=9

Subtract 10 from both sides

10+y-10=9-10

y=-1

Hence, the solution of system of equations 5x+y=9 and 3x+2y=4 is (2,-1).

Learn more about system of equations from here brainly.com/question/13729904

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6 0
2 years ago
If cos(x) = Three-fourths and tan(x) &lt; 0, what is cos(2x)?
makvit [3.9K]

Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

\sin^2(x) + \cos^2(x) = 1sin

2

(x)+cos

2

(x)=1

So we have:

\sin^2(x) + (1/4)^2 = 1sin

2

(x)+(1/4)

2

=1

\sin^2(x) + 1/16= 1sin

2

(x)+1/16=1

Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

2

(x)=15/16

Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

tan(x) < 0

It means that:

sin(x) < 0

So, we have:

\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

15

/4

sin(2x) is then calculated as:

\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)

So, we have:

\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗

4

15

∗

4

1

This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

6 0
2 years ago
Read 2 more answers
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