That table salt has a high melting point and mercury's melting point is low.
The equation is given is of combustion of ethanol.
Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.
The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.
Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.
The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.
To conclude with we can say that the given reaction of combustion of ethanol. Ethanol with oxygen given carbon dioxide with water on reaction.
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Answer:
Al has a 3+ charge, and SO4 has a 2- charge. So, it takes 3 of the SO4 anions to balance 2 of the Al cations. So, you get Al2(SO4)3
Answer:
The percentage of amine is protonated is 63,07%
Explanation:
The reaction of an amine RNH₃ (weak base) with water is:
RNH₃ + H₂O ⇄ RNH₄⁺ + OH⁻
The kb is defined as:
![kb = \frac{[RNH_{4}^+][OH^-]}{[NH_{3}]}](https://tex.z-dn.net/?f=kb%20%3D%20%5Cfrac%7B%5BRNH_%7B4%7D%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BNH_%7B3%7D%5D%7D)
As kb = 4,004x10⁻⁵ and [OH⁻] is 
:
![4,004x10^{-5} = \frac{[RNH_{4}^+][2,34x10^{-5}]}{[NH_{3}]}](https://tex.z-dn.net/?f=4%2C004x10%5E%7B-5%7D%20%3D%20%5Cfrac%7B%5BRNH_%7B4%7D%5E%2B%5D%5B2%2C34x10%5E%7B-5%7D%5D%7D%7B%5BNH_%7B3%7D%5D%7D)
1,708 = [RNH₄⁺] / [RNH₃] <em>(1)</em>
As the total amine is a 100%:
[RNH₄⁺] + [RNH₃] = 100% <em>(2)</em>
Replacing (1) in (2):
1,708 [RNH₃]+ [RNH₃] = 100%
2,708 [RNH₃] = 100%
[RNH₃] = 36,93%
Thus,
<em> [RNH₄⁺] = 63,07%</em>
The percentage of amine protonated is 63,07%
I hope it helps!
