This is an example of Charles’ Law problems, the basic equation is: V1/T1 = V2/T2. One vital thing to recall for all gas law problems is that the temperature must be in Kelvin (not Celsius).
So our given is 10.0 C = 283 K. So
V1/T1 = V2/T2
733/283 = 950/T2
T2 = 367 K
4 moles of hydrogen = 4 * 1.008 = 4.032 grams
1 mole of helium = 4.003 grams
Difference is 4.032 - 4.003
= 0.029 g
Answer:
32000atm
Explanation:
Using Boyle's law equation;
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (
V2 = final volume (L)
According to the question below:
P1 = 160.0 atm
P2 = 3.0 atm
V1 = 600L
V2 = ?
Using P1V1 = P2V2
160 × 600 = 3 × V2
96000 = 3V2
V2 = 96000/3
V2 = 32000atm
Explanation:
It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.
or 
So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.