All categories

3 years ago

Rounding decimals 3.5691 thousandths

Mathematics

2 answers:

yan [13]3 years ago

7 0

<h3>Answer: 3.569</h3>

Explanation:

There's a 9 in the thousandths place. The next digit to the right is 1, which is not 5 or more. So we'll just drop that 1 and that's why the answer is 3.569

evablogger [386]3 years ago

3 0

Answer:

3.569

Step-by-step explanation:

Rounding is the process of shortening a number to a certain number of digits by finding the closest number with the desired number of digits. When rounding, look one digit to the right of the desired decimal place. In this case, you want the thousandths place. The thousandths place is 3 digits after the decimal, so look at the number next to the 9, the 1. If the number is 5 or greater round up, if it is 4 or less round down. Therefore, 3.5691 should be rounded down to 3.569.

Other examples include,

4.8736 being rounded up to 4.874

6.3168 being rounded up to 6.317

9.7340 being rounded down to 9.734

You might be interested in

50 points if you can help me??!!!!

Sedaia [141]

Answer:

The answer is C. An absolute value will never have a negative in it.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th

Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34$

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{990 - 975}{9.34}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463

X = 960

$Z = \frac{X - \mu}{s}$

$Z = \frac{960 - 975}{9.34}$

$Z = -1.61$

$Z = -1.61$ has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0

3 years ago

Point Q is plotted on the coordinate grid. Point P is at (10, −20). Point R is vertically above point Q. It is at the same dista

bixtya [17]

Answer:

Point R is at (−20, 10), a distance of 30 units from point Q

Step-by-step explanation:

Q has coordinates (-20,-20).

P has coordinates (10,-20)

Since point R is vertically above point Q, it will have the same x-coordinate as Q.

Let R have coordinates (-20,y).

It was given that;