If you would like to know how much money will Gerold have at the end of 5 years, you can calculate this using the following steps:

1 year: $118 + 6% * $118 = 118 + 6/100 * 118 = 118 + 7.08 = $125.08
2 year: $125.08 + 6% * $125.08 = 125.08 + 6/100 * 125.08 = 125.08 + 7.50 = $132.58
3 year: $132.58 + 6% * $132.58 = 132.58 + 6/100 * 132.58 = 132.58 + 7.95 = $140.53
4 year: $140.53 + 6% * $140.53 = 140.53 + 6/100 * 140.53 = 140.53 + 8.43 = $148.96
5 year: $148.96 + 6% * $148.96 = 148.96 + 6/100 * 148.96 = 148.96 + 8.94 = $157.9

The correct result would be $157.9.

6 0

3 years ago

The set of integers greater than 50

UkoKoshka [18]

The set of integers greater than 50 are (51,52,53,54...)

5 0

3 years ago

. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the

inn [45]

Answer:

The first car was traveling 70 mph, while the second was driving 50 mph.

Step-by-step explanation:

Set the cars as a proportion:

$\frac{210}{x + 2} = \frac{150}{x}$

X represents the speed of the second car. By cross multiplying, you get the following equation:

$210x = 150(x + 20)$

You solve by distributing 150 to get 210x = 150x + 3000.

Solving for x gets you 50.

That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.

4 0

3 years ago

I have attached the picture

Alchen [17]

(a) c.

(b) a.

. hope this helps you..

8 0

2 years ago