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Lostsunrise [7]
2 years ago
11

Prime factorisation of 500​

Mathematics
1 answer:
Andrews [41]2 years ago
6 0

\boxed{\underline{\bf \: ANSWER}}

2 <u>| 500</u>

2 <u>| 250</u>

5 <u>| 125</u>

5 <u>| 25</u>

5 <u>| 5</u>

1 <u>| 1</u>

Prime factorisation of <u>500 = 2 × 2 × 5 × 5 × 5 × 1</u>

_____

Hope it helps.

ᏒᎯᎨᏁᏰᎾᏯᏕᎯᏝᎿ2222

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Answer:

r=3.5\%

Step-by-step explanation:

we know that

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We are given a sequence of five non-zero numbers, where the sum of each term and its neighboring terms is 15 or 25. Find the sum
PSYCHO15rus [73]

We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.

We will see that the sum tends to infinity.

So we have 5 terms;

A, B, C, D, E.

We know that the sum of each term and its neighboring terms is 15 or 25.

then:

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Now, we want to find the sum of all the terms in the sequence (not only the 5 given).

Then let's assume we write the sum of infinite terms as:

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So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.

Then we have:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) +  ... \to \infty

If you want to learn more, you can read:

brainly.com/question/21885715

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