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Solnce55 [7]
3 years ago
11

Give some sources of potential difference (P.D) that you know.

Physics
1 answer:
Anna [14]3 years ago
4 0
  1. All type of Batteries
  2. secondary batteries ( Rechargeable battery) example car battery etc . these battery contain Sulphuric acid as there electrolytic
  3. Primary Battery (Non Recharge) example Dry cell , pencil cell . These battery contain chemicals they react when we use the battery and can't be recharged again we need to replace each and every time
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The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in
lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m

or

\tau=0.5\ N-m

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

6 0
4 years ago
An object is moving but we don't know its mass or velocity. A force of 20 newtons to the right
jok3333 [9.3K]

The impulse is (force) x (time) = (20 N) x (20 sec) = 400 N-sec

When we grind through the units, we find that the [newton-second]
is exactly the same as the [kilogram-meter/sec] unit-wise, and once
we know that, it doesn't surprise us to learn that impulse is equivalent
to a change in momentum (mass x speed ... also kg-m/s).

So this impulse exerted on the moving object adds 400 kg-m/s of
linear momentum to its motion, directed to the right.  That may or
may not be the total change in its momentum during that 20-sec,
because our 20-N may not be the only force acting on it.


8 0
3 years ago
A satellite orbiting above the earth needs no power source to keep orbiting the earth.
abruzzese [7]

Answer:

True

Explanation:

The earths gravitational pull keeps it consistent with its orbit.

8 0
3 years ago
Read 2 more answers
Using Boyle's law, predict what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.
Savatey [412]

Answer:

Balloon that an ocean diver takes to a pressure of 202 k Pa will get reduced in size that is the volume of the balloon will get reduced

Explanation:

4 0
3 years ago
Una persona de 80kg intenta bajar de peso subiendo una montaña para quemar el equilante a una rebanada de pastel de chocolate (7
SCORPION-xisa [38]

Answer:

Explanation:

An 80kg person tries to lose weight by climbing a mountain to burn the equivalent of a large slice of a rich chocolate cake (700kcl). How high should you climb?

Given that,

A person of mass

M = 80kg

The person is climbing a stair case and he burn an energy of 700 kcl

We know that 1kcl = 4184J

Then, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10^6 J

We want to find height of stairs the person will climb when he Loss 700kcl. The energy he burns will be converted to the potential energy

P.E is calculated using

P.E = mgh

Where

m is mass in kg

g is gravitational constant g = 9.81m/s2

h is the height of stairs he climb in metre

Then,

P.E = energy burn

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10^6

h = (2.9288 × 10^6) / (80 × 9.81)

h = 3731.91m

So, the person will climb 3731.91m before he losses 700kcl

In espanyol

Dado que,

Una persona de masa

M = 80 kg

La persona está subiendo una escalera y quema una energía de 700 kcl.

Sabemos que 1kcl = 4184J

Entonces, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10 ^ 6 J

Queremos encontrar la altura de las escaleras que la persona subirá cuando pierda 700kcl. La energía que quema se convertirá en energía potencial.

P.E se calcula utilizando

P.E = mgh

Dónde

m es masa en kg

g es constante gravitacional g = 9.81m / s2

h es la altura de las escaleras que sube en metros

Entonces,

P.E = quema de energía

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10 ^ 6

h = (2.9288 × 10 ^ 6) / (80 × 9.81)

h = 3731.91m

Entonces, la persona subirá 3731.91m antes de perder 700kcl

5 0
4 years ago
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