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Stels [109]
3 years ago
11

The body of knowledge that deals with Earth and its place in the universe is called _____________?

Chemistry
1 answer:
lakkis [162]3 years ago
7 0

Answer:

Cosmology is a branch of astronomy that involves the origin and evolution of the universe, from the Big Bang to today and on into the future. According to NASA, the definition of cosmology is "the scientific study of the large scale properties of the universe as a whole."

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Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.
Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n}{W_s}

where,

n = moles of solute

W_s = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg

Now put all the given values in the formula of molality, we get

Molality=\frac{0.241}{0.0137kg}=17.6mole/kg

Therefore, the molality of solution is 17.6 mole/kg

3 0
3 years ago
Free-energy change, ΔG∘, is related to cell potential, E∘, by the equationΔG∘=−nFE∘where n is the number of moles of electrons t
mart [117]

Answer:

a)\Delta G=372490 J

b)\Delta G=-568614 J

Explanation:

a) The reaction:

Mg(s) +Fe^{2+}(aq) \longrightarrow Mg^{2+}(aq) + Fe(s)

The free-energy expression:

\Delta G=-n*F*E

E=E_{red}-E_{ox]

The element wich is reduced is the Fe and the one that oxidates is the Mg:

-0.44V=E_{red}-(-2.37V)=1.93V

The electrons transfered (n) in this reaction are 2, so:

\Delta G=-2mol*96500 C/mol * 1.93 V

\Delta G=-372490 J

b) If you have values of enthalpy and enthropy you can calculate the free-energy by:

\Delta G=\Delta H - T* \Delta S

with T in Kelvin

\Delta G=-675 kJ*\frac{1000J}{kJ} - 298K*-357 J/K

\Delta G=-568614 J

7 0
3 years ago
the atomic mass of an element is A. the amount of electrons the element has B. the number of neutrons an element has C. the numb
vredina [299]
C. the number of protons and neutrons an element has in its nucleus
5 0
3 years ago
Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. CO + O2 → CO2
liberstina [14]

Answer:

2co + o2 > 2co2

Explanation:

so that is tye answer

3 0
4 years ago
Read 2 more answers
Which of the following statements about electronic configurations of atoms and mononuclear ions, and atomic orbital quantum numb
ruslelena [56]

Answer:

a. The electronic configuration of the hydride anion is 1s2. TRUE

b. The valence electronic configuration of strontium is 4d2.  FALSE

c. For a given value of l the number of possible values of ml is 2l + 1.  TRUE

d. Cu+ has the same electronic configuration as Ni.  TRUE

e. The magnetic quantum number is never larger than the principle quantum number (for a given orbital). TRUE

Explanation:

a. The electronic configuration of the hydride anion is 1s² is true since the hydriden anion is the hdrogen atom which has gained an electron and we will add that electron to the 1s¹ configuration of H.

b. The valence electronic configuration of strontium is 4d2 is false since Sr is an element of period 5 , therefore its valece electrons are in in period five and it has 2 electrons because Sr belongs to group 2.

c. For a given value of l the number of possible values of ml is 2l+1 is true since this number gives the magnetic orientation for the sublevel. Thus for s there is only one orientation, then ml = 2 (0 ) +1 . Por p with  l equal to 1 we have three possible orientations : 2(1) + 1 =3. The d and f sublevels have 10 and 14 orientations.

d. Cu⁺ has the the same electronic configuration as Ni is true since Cu, atomic number 29, has one more electron than its neighbor Ni with an atomic number of 28. If we remove one electron from copper we are gong to have the same 28 electrons niquel has in its neutral state.

e. The magnetic quantum number is never larger than the principal quantum  number for a given orbital is true since l, the magnetic quantum number can have values up to n-1, the principal quantum number.

4 0
3 years ago
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