] Ceres is composed of rock and ice and is estimated to comprise approximately one third of the mass of the entire asteroid belt. Ceres is the only object in the asteroid belt known to be rounded by its own gravity (though detailed analysis was required to exclude 4 Vesta). From Earth, the apparent magnitude of Ceres ranges from 6.7 to 9.3, peaking once every 15 to 16 months,[21]hence even at its brightest it is too dim to be seen with the naked eye except under extremely dark skies.
Sound and water waves are longitudinal waves, they require a medium to travel through and occilate particles 90 degrees to the wave motion
Light is a transverse wave. It doesnt require a medium to travel through.
All three reflect, refract and diffract
Light is difficult to think of because it acts in ways which waves cannot explain in some cirumstances. It acts like a particle (called photons) in some conditions, but acts like a normal sound or water wave does in others. Try not to get too caught up in light being a wave or a particle because even physists dont know how to explain it yet.
the higher concentration of molecules, the faster a reaction can occur
Answer
given,
mass of copper rod = 1 kg
horizontal rails = 1 m
Current (I) = 50 A
coefficient of static friction = 0.6
magnetic force acting on a current carrying wire is
F = B i L
Rod is not necessarily vertical
![F_x =i L B_d](https://tex.z-dn.net/?f=F_x%20%3Di%20L%20B_d)
![F_y= i L B_w](https://tex.z-dn.net/?f=F_y%3D%20i%20L%20B_w)
the normal reaction N = mg-F y
static friction f = μ_s (mg-F y )
horizontal acceleration is zero
![F_x-f = 0](https://tex.z-dn.net/?f=F_x-f%20%3D%200)
![iLBd = \mu_s(mg-F_y )](https://tex.z-dn.net/?f=iLBd%20%3D%20%5Cmu_s%28mg-F_y%20%29)
B_w = B sinθ
B_d = B cosθ
iLB cosθ= μ_s (mg- iLB sinθ)
![B = \dfrac{\mu_smg}{i(cos\theta +\mu_s sin\theta)}](https://tex.z-dn.net/?f=B%20%3D%20%5Cdfrac%7B%5Cmu_smg%7D%7Bi%28cos%5Ctheta%20%2B%5Cmu_s%20sin%5Ctheta%29%7D)
![\theta =tan{-1}{\mu_s}](https://tex.z-dn.net/?f=%5Ctheta%20%3Dtan%7B-1%7D%7B%5Cmu_s%7D)
![\theta =tan{-1}{0.6}](https://tex.z-dn.net/?f=%5Ctheta%20%3Dtan%7B-1%7D%7B0.6%7D)
![\theta = 31^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2031%5E0)
![B = \dfrac{0.6\times 1 \times 9.8}{50(cos31^0 +0.6 sin31^0)}](https://tex.z-dn.net/?f=B%20%3D%20%5Cdfrac%7B0.6%5Ctimes%201%20%5Ctimes%209.8%7D%7B50%28cos31%5E0%20%2B0.6%20sin31%5E0%29%7D)
B = 0.1 T