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Katen [24]
2 years ago
11

A string is wrapped around a pulley with a radius of 2.0 cm and no appreciable friction in its axle. The pulley is initially not

turning. A constant force of 50 N is applied to the string, which does not slip, causing the pulley to rotate and the string to unwind. If the string unwinds 1.2 m in 4.9 s, what is the moment of inertia of the pulley?
Physics
2 answers:
stiks02 [169]2 years ago
5 0

Answer:

2

Explanation:

2

sveta [45]2 years ago
5 0

Answer:

Moment of inertia = I = 0.2 kg.m^2

Explanation:

According to equation of motion:

s = ½ at^2

a = 2s/t^2

a = (2 × 1.2)/4.9^2 = 0.09996 m/s^2

The Linear and angular acceleration will be:

a =rα

α = a/r = 0.09996/0.02 = 4.9979 rad/s^2

Torque = T = rF = (0.02)(50) = 1 N

Now,

Moment of inertia = I = T/ α = 1/(4.9979) = 0.2 kg.m^2

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In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result
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According to the given statement:

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  •    Z = R + R₂
<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

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<h3>According to the given information:</h3>

The impedance of a series circuit is

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The initial resistance impedance shifts to when we add another resistor to the series

              Z² = (R + R₂) ² + (X_L - X_C) ²

Let's examine this sentence.

  • The frequency response remains unchanged, which is the first thing we notice.
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           Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

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