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3 years ago

7

Jet fuel is sold by the pound. Your jet needs 1,500 gallons of fuel. Jet fuel weighs 7.0 pounds per gallon and costs $12.00 per

kg. If there are 2.2 pounds in one kilogram, how much do you owe the airport in order to fill your jet?

1 answer:

galben [10]3 years ago

5 0

Answer:

$ 57,272.73

Explanation:

Create a lengthy equation to convert the units you are given to the units you need to answer the question.

Your starting with gallons and pounds and you need your answer to be in Dollars.

$ 12.00 1 kg 7.0 lb 1500 gal

------------ X ----------- X ------------ X -------------- = $ 57,272.73

1 kg 2.2 lb 1 gal 1

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How does Newton's first law of motion affect people in a car crash?

kap26 [50]

Answer:

When the car crashes there is no balanced force acting on the person so they continue forward in the car

Explanation:

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4 years ago

(a) What is the cost of heating a hot tub containing 1440 kg of water from 10.0°C to 40.0°C, assuming 75.0% efficiency to take h

BaLLatris [955]

Answer:

a) $E = 6.024\,USD$ , For m kilograms, it is 4184m J., 3600000 joules, b) $i = 88.200\,A$

Explanation:

a) The amount of heat needed to warm water is given by the following expression:

$Q_{needed} = m_{w}\cdot c_{w}\cdot (T_{f}-T_{i})$

Where:

$m_{w}$ - Mass of water, measured in kilograms.

$c_{w}$ - Specific heat of water, measured in $\frac{J}{kg\cdot ^{\circ}C}$ .

$T_{f}$ , $T_{i}$ - Initial and final temperatures, measured in $^{\circ}C$ .

Then,

$Q_{needed} = (1440\,kg)\cdot \left(4184\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (40^{\circ}C - 10^{\circ}C)$

$Q_{needed} = 180748800\,J$

The energy needed in kilowatt-hours is:

$Q_{needed} = 180748800\,J\times \left(\frac{1}{3600000}\,\frac{kWh}{J} \right)$

$Q_{needed} = 50.208\,kWh$

The electric energy required to heat up the water is:

$E = \frac{50.208\,kWh}{0.75}$

$E = 66.944\,kWh$

Lastly, the cost of heating a hot tub is: (USD - US dollars)

$E = (66.944\,kWh)\cdot \left(0.09\,\frac{USD}{kWh} \right)$

$E = 6.024\,USD$

The heat needed to raise the temperature a degree of a kilogram of water is 4184 J. For m kilograms, it is 4184m J. Besides, a kilowatt-hour is equal to 3600000 joules.

b) The current required for the electric heater is:

$i = \frac{Q_{needed}}{\eta \cdot \Delta V \cdot \Delta t}$

$i = \frac{180748800\,J}{0.75\cdot (220\,V)\cdot (3.45\,h)\cdot \left(3600\,\frac{s}{h} \right)}$

$i = 88.200\,A$

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3 years ago

Find the angle between the vectors. (First find an exact expression and then approximate to the nearest degree.) a = 2i − 5j + k

EastWind [94]

Answer:

Angle=70°

Explanation:

Given data

a=2i-5j+k

b=9i-k

To find

Angle Θ

Solution

As we know from dot product rule that

$a.b=|a||b|cos\alpha \\cos\alpha=\frac{a.b}{|a||b|}\\\alpha=cos^{-1} (\frac{a.b}{|a||b|})$

First we need to find a.b

As

i.i=j.j=k.k=1

i.j=i.k=j.k=0

So

$a.b=(18)+(-1)\\a.b=17$

Now for |a| and |b|

$|a|=\sqrt{x^{2} +y^{2}+z^{2} }\\|a|=\sqrt{(2)^{2} +(-5)^{2}+(1)^{2} }\\ |a|=5.477\\And\\|b|=\sqrt{x^{2} +y^{2}+z^{2} }\\|b|=\sqrt{(9)^{2} +(0)^{2}+(-1)^{2} }\\|b|=9.055$

So the angle is given as

$\alpha=cos^{-1} (\frac{a.b}{|a||b|})\\\alpha=cos^{-1} (\frac{17}{(5.477)*(9.055)})\\\alpha =70^{o}$

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3 years ago

An AED should only be used if a person is too tired to continue with chest compressions.

malfutka [58]

The given statement "An AED should only be used if a person is too tired to continue with chest compressions" is false.

Answer: Option B

<u>Explanation:</u>

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For example, consider you come across the victim in a narrow place and you have two helpers: Rescuer 2 arrives with the AED (automated external defibrillator) and puts it on the opposite side from Rescuer 1, who does chest compressions. Rescuer 2 turns on the AED and fixes the electrodes to the victim's chest, connecting wires to the AED if necessary. Rescuer 1 can continue CPR (Cardiopulmonary resuscitation) by placing electrodes until the victim's heart rate has been analysed.

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3 years ago

A projectile is fired into the air at a 35o angle to the horizontal and an initial velocity of 120 m/s. what are the x and y com

Anarel [89]

Answer:

See below

Explanation:

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Y component = 120 * sin 35° = 68.829 m/s

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2 years ago