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Anastasy [175]
3 years ago
12

Use the substitution method to solve the system of equations. Choose the correct ordered pair. y=6x-4 y=7x-7 A. (4, 18) B. (5, 9

) C. (3, 14) D. (2, 11)
Mathematics
1 answer:
White raven [17]3 years ago
5 0

Answer:

C (3,14)

Step-by-step explanation:

y=6x-4

y=7x-7

6x-4=7x-7

-x=-3

x=3

y=6*3-4=14

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Suppose we want to estimate the average weight of an adult male in Mexico. We draw a random sample of 2,000 men from a populatio
LenKa [72]

Answer:

1.- CI = 94% (  μ₀ -  1,04   <  x   <   μ₀ +  1,04 )

2.- CI = 98 % ( μ₀ - 2,05  <  x   <   μ₀ + 2,05 )

3.- CI = 96 %  (  μ₀ - 1,75  <  x   <   μ₀  + 1,75 )

Step-by-step explanation:

Sample size      n  = 3000000

Sample mean   x  =  200

Standard deviation   s  =  30

From  z-table values of z(c):

CI  94 %        Confidencial level   α = 6 %   α = 0,06   z(c) = 1,55

CI  98 %        Confidencial level   α = 2 %   α = 0,02   z(c) = 2,05

CI  96 %        Confidencial level   α = 4 %   α = 0,04   z(c) =  1,75

MOE = z(c) * σ/√n

1.-MOE =  1,55* 30 / √2000    MOE = 1,04

2.-MOE = 2,05*30/√2000      MOE = 1,38

3.-MOE = 1,75*30/√2000        MOE = 1,17

Then CI

1.-  CI = 94 %     (  μ₀ -  MOE <  x  <   μ₀ -  MOE )

     CI  =  (  μ₀ -  1,04   <  x   <   μ₀ +  1,04 )

2.-CI = 98 %

     CI  = (    μ₀ - 2,05  <  x   <   μ₀ + 2,05 )

3.- CI = 96 %

     CI = (  μ₀ - 1,75  <  x   <   μ₀  + 1,75 )

7 0
3 years ago
Given a normal distribution with mu equals 100μ=100 and sigma equals 10 commaσ=10, complete parts​ (a) through​ (d). loading...
m_a_m_a [10]

I believe the parts are:

A. What is the probability that Upper X greater than 95X>95​?

B. What is the probability that Upper X less than 75X<75?

C.What is the probability that Upper X less than 85X<85 and Upper X greater than 125X>125?

D. 95​% of the values are between what two​ X-values (symmetrically distributed around the​ mean)?

 

<u>Solution:</u>

We use the equation for z score:

z = (X – μ) / σ

Then use the standard normal probability tables to locate for the value of P at indicated z score value.

 

A. Z = (95 – 100) / 10 = - 0.5

Using the tables, the probability at z = -0.5 using right tailed test is:

P = 0.6915

 

 

B. Z = (75 – 100) / 10 = - 2.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0062

 

 

C. Z = (85 – 100) / 10 = - 1.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0668

 

Z = (125 – 100) / 10 = 2.5

Using the tables, the probability at z = 2.5 using right tailed test is:

P = 0.0062

 

So the probability that 85<X and X>125 is:

P(total) = 0.0668 + 0.0062

P(total) = 0.073

 

 

D. P(left) = 0.025, Z = -1.96

P(right) = 0.975, Z = 1.96

 

The X’s are calculated using the formula:

X = σz + μ

 

At Z = -1.96

X = 10 (-1.96) + 100 = 80.4

 

At Z = 1.96

X = 10 (1.96) + 100 = 119.6

 

<span>So 95% of the values are between 80.4 and 119.6 (80.4< X <119.6).</span>

7 0
4 years ago
The path of a football can be modelled by the equation, h=-10d2+120d , where h represents the height, in metres, of the football
Marta_Voda [28]

Answer:

12 m

Step-by-step explanation:

The path of a football has been modeled by the equation:

h= -10d^2+120d

where h represents the height and d represents the horizontal distance.

When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.

=> 0= -10d^2+120d

=> 10d^2 - 120d = 0

d(10d - 120) = 0

∴ d = 0 m

and

10d - 120 = 0

=> d = 120 / 10 = 12 m

There are two solutions for d when h = 0 m.

The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.

The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m

3 0
3 years ago
The absolute value of a number is
makvit [3.9K]

Answer: the magnitude of a real number without regard to its sign.

Step-by-step explanation:

Meaning whether it is 5 or -5 the absolute value is 5 for both because that is their distance from zero.

7 0
3 years ago
Read 2 more answers
Find all the real square roots of <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-9%7D%7B16%7D%20" id="TexFormula1" title=" \fra
svet-max [94.6K]
Since -\dfrac9{16} is negative, it doesn't have any real roots.
6 0
3 years ago
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