2nd equation:
8 x-y=10 ⇒ y= 8 x-10
We will switch that in 1st equation:
8 x-10=x²+12 x+30, or:
x² + 4 x +40 = 0, a=1,B=4, c=40
Discriminant : D= b² - 4 ac= 16 - 160 = -144 and because it is negative there are no real solutions.
Answer: D)
For this case we have the following equation:
12x2-5x-2 = 0
Using the resolver we have:
x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
Substituting values we have:
x = (- (- 5) +/- root ((- 5) ^ 2 - 4 * 12 * (- 2))) / (2 * 12)
Rewriting:
x = (5 +/- root (25 +96))) / (2 * 12)
x = (5 +/- root (121))) / (2 * 12)
x = (5 +/- 11) / (2 * 12)
Answer:
One root is positive and another is negative.
Answer:
12 + 2g ?
Step-by-step explanation:
6 + 6 = 12. g + g = 2g. So together you get 12 + 2g. I am not 100% sure.
