Answer:
So, the probability that a randomly selected Korean driver will take two or more non-home-based trips per day is P=0.32.
Step-by-step explanation:
We know that the number of non-home-based trips per day taken by drivers in Korea was modeled using the Poisson distribution with λ = 1.15.
We have the Poisson formula:
![P(X=k)=\frac{\lambda^k\cdot e^{-\lambda}}{k!}](https://tex.z-dn.net/?f=P%28X%3Dk%29%3D%5Cfrac%7B%5Clambda%5Ek%5Ccdot%20e%5E%7B-%5Clambda%7D%7D%7Bk%21%7D)
We calculate:
![P(X\geq 2)=1-P(X=0)-P(X=1)\\\\P(X\geq 2)=1-\frac{1.15^0\cdot e^{-1.15}}{0!}-\frac{1.15^1\cdot e^{-1.15}}{1!}\\\\P(X\geq 2)=1-0.32-0.36\\\\P(X\geq 2)=0.32](https://tex.z-dn.net/?f=P%28X%5Cgeq%202%29%3D1-P%28X%3D0%29-P%28X%3D1%29%5C%5C%5C%5CP%28X%5Cgeq%202%29%3D1-%5Cfrac%7B1.15%5E0%5Ccdot%20e%5E%7B-1.15%7D%7D%7B0%21%7D-%5Cfrac%7B1.15%5E1%5Ccdot%20e%5E%7B-1.15%7D%7D%7B1%21%7D%5C%5C%5C%5CP%28X%5Cgeq%202%29%3D1-0.32-0.36%5C%5C%5C%5CP%28X%5Cgeq%202%29%3D0.32)
So, the probability that a randomly selected Korean driver will take two or more non-home-based trips per day is P=0.32.
Answer:
n + 7/5
Step-by-step explanation:
<u>Solve</u>
Let "n" be the varable.
Add 7 = +
Then, Divideby 5 = ÷
Therefore, the equation for this is n + 7 ÷ 5
n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
The answer is 2/3 shirt per hour.
https://youtu.be/GZcm4mswivc
espero que te ayude