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Arte-miy333 [17]
3 years ago
9

What would happen if our intestines were not coiled (twisted) inside our body?

Chemistry
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

If there is a change in the natural shape of the intestines, this can be known as a twisted bowel. A twist in the small intestine is referred to as a volvulus. Twists in the large intestine are known as a colonic volvulus. These abnormal twists or loops can cause an obstruction or other medical conditions which could be fatal. If signs of twisting bowel present, it is important to seek medical attention as quickly as possible.

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In a bond Between fluorine and bromine which direction will the bond dipole point?
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Answer: Bond Polarity | Chemistry for Non-Majors - Lumen Learning

Explanation:

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The oxidation number of Na in NaCl a. 0 b. -1 c. +1 d. -2 e. +2
Dahasolnce [82]
NaCl:

Na = + 1

Cl = - 1

hope this helps!
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3 years ago
Enzymatic breakdown of which of the following compounds doesn't begin until it reaches the stomach?A) lipidsB) carbohydrates C)
kvv77 [185]

Answer is proteins (C)

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3 years ago
A 55.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
balu736 [363]

Answer:

0.14 M

Explanation:

To determinate the concentration of a new solution, we can use the equation below:

C1xV1 = C2xV2

Where C is the concentration, and V the volume, 1 represents the initial solution, and 2 the final one. So, first, the initial concentration is 1.50 M, the initial volume is 55.0 mL and the final volume is 278 mL

1.50x55.0 = C2x278

C2 = 0.30 M

The portion of 139 mL will be the same concentration because it wasn't diluted or evaporated. The final volume will be the volume of the initial solution plus the volume of water added, V2 = 139 + 155 = 294 mL

Then,

0.30x139 = C2x294

C2 = 0.14 M

4 0
3 years ago
Read 2 more answers
How many grams of Fe can be produced when 5.50 g of Fe2O3 reacts?
vichka [17]

Answer:

3,85 g of Fe

Explanation:

1- The first thing to do is calculate the molar mass of the Fe2O3 compound. With the help of a periodic table, the weights of the atoms are searched, and the sum is made:

Molar mass of Fe2O3 = (2 x mass of Fe) + (3 x mass of O) = 2 x 55.88 g + 3 x 15.99 g = 159.65 g / mol

Then, one mole of Fe2O3 has a mass of 159.65 grams.

2- Then, the relationship between the Fe2O3 that will react and the iron to be produced. With the previous calculation, we can say that with one mole of Fe2O3, two moles of Fe can be produced. Passing this relationship to the molar masses, it would be as follows:

1 mole of Fe2O3_____ 2 moles of Fe

159.65 g of Fe2O3_____ 111.76 g of Fe

3- Finally, the calculation of the mass that can be produced of Fe is made, starting from 5.50 g of Fe2O3

159.65 g of Fe2O3 _____ 111.76 g of Fe

5.50 g of Fe2O3 ______ X = 3.85 g of Fe

<em>Calculation: 5.50 g x 111.76 g / 159.65 g = 3.85 g </em>

The answer is that 3.85 g of Fe can be produced when 5.50 g of Fe2O3 react

7 0
3 years ago
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