Explanation:
They are related by the the density triangle.
Explanation:
They are related by the the density triangle.
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d =
m
V
m = d×V
V =
m
d
DENSITY
Density is defined as mass per unit volume.
d =
m
V
Example:
A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?
Step 1: Calculate the volume
V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³
Step 2: Calculate the density
d =
m
V
=
433
g
200
c
m
³
= 2.16 g/cm³
MASS
d =
m
V
We can rearrange this to get the expression for the mass.
m = d×V
Example:
If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?
m = d×V = 500 mL ×
1.11
g
1
m
L
= 555 g
VOLUME
d =
m
V
We can rearrange this to get the expression for the volume.
V =
m
d
Example:
What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.
Step 1: Convert kilograms to grams.
14.83 kg ×
1000
g
1
k
g
= 14 830 g
Step 2: Calculate the volume.
V =
m
d
= 14 830 g ×
1
c
m
³
19.32
g
= 767.6 cm³
True because molo means two so you would need more than 1 atom
Answer:
3.711 L
Explanation:
The formula you need to use is the following:

3.4L / 298 K = V2 / 273 K
V2 = 3.711 L
Chem bonds by exchanged charges create new characteristics as a result
Answer:
12 g of choloracetic acid
Explanation:
The buffer equilibrium is:
HCH₂ClCO₂ ⇄ CH₂ClCO₂⁻ + H⁺
pka= -log ka =
Ka: 1,3x10⁻³ = [CH₂ClCO₂⁻] [H⁺] / [HCH₂ClCO₂]
By Henderson-Hasselbalch equation:
pH = pka + log₁₀ [A⁻] / [HA]
3,01 = 2,89 + log₁₀ [A⁻] / [HA]
1,318 = [A⁻] / [HA]
As molar concentration of chloroacetic acid (HA) is 0,20M
[A⁻] = 0,26 mol/L
The volume is 500 mL ≡ 0,5 L
0,26mol/L × 0,5 L = 0,13 moles of chloroacetic acid. In grams:
0,13 mol × (94,5g / 1mol) = <em>12 g of choloracetic acid</em>
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I hope it helps!