Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)
<h3>Strength of electrolytes</h3>
- Strong electrolytes: are completely ionized in aqueous solution.
- Weak electrolytes: are partially ionized in aqueous solution.
Let's consider the ionization of ammonium hydroxide, which is a weak base.
NH₄OH ⇄ NH₄⁺ + OH⁻
Why is it considered a weak base?
a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.
b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.
c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.
d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.
Learn more about weak bases here: brainly.com/question/322250
#SPJ1
The dissolution of a solute in a solvent to form a solution usually occur in three steps, which are delta H1, delta H2 and delta H3.
For dissolving an ionic solid, the lattice energy, which is the energy that is holding the ionic particles in place correspond to DELTA H2 and it is the energy that must be conquered. The higher the charge in the ionic solid, the higher the lattice energy. The lattice energy must be overcome in order for the solid to dissolve.
"I" symbol means the current goes through the system (imagine the 'I' being a line, like a circuit connecting [power to the device]) "O" symbol means the current does not go through the system. ( the circle is an open circuit, having no power flowing through it
Due to energy being a reactant instead of a product, the process is endothermic. The system must absorb a quantity of energy before it can react, so it must be an endothermic system.
Answer: B
Explanation: molarity = concentration c= n/V = 0.5 mol/ 0.05 l = 10 mol/l
