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OLga [1]
3 years ago
5

Which molecule can form hydrogen bonds with others like it? A. Co2 B. HCI C. CF4 D. NH3

Chemistry
1 answer:
iren2701 [21]3 years ago
3 0

Answer: D NH3

Explanation:When NH3 , popularly called ammonia react with water, the water molecules dissociate into it's components H^+ and OH^-,the H^+ which is the cation forms an hydrogen bond with ammonia NH3 to form NH4^+ while the anion form is OH^-.the reaction itself is a dipolar reaction .

NH3 + H2O_____NH4^+ +OH^-

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Which of the following models best describes the arrangement of valence electrons in metals?
Lana71 [14]

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A sea of electrons.

7 0
4 years ago
I’m not sure how to do this, please help. It’s a mole to mole stoich worksheet.
wlad13 [49]

Answer: 4.05 mol O2, 15.36 mol H2O

Explanation:

I can answer each question individually if you post them individually.

2a. 3.24 mol NH3 * (5 mol O2 / 4 mol NH3) = 4.05 mol O2

2b. 12.8 mol O2 ( 6mol H2O/ 5 mol O2) = 15.36 mol H2O

Essentially what I did was dimensional analysis. Multiplying in a way that the units cancel out so the only thing remains is what each question asks for.

3 0
3 years ago
The molecular weight of an ionic compound is 118.9 g/mol. the ions in the unknown are sodium, oxygen, and bromine. what is the n
vodka [1.7K]
Answer is: the name of the unknown oxyanion is hypobromite.
<span>
M(NaBrO</span>ₓ) = 118.9 g/mol; <span>molecular weight of an ionic compound.
</span>M(Na) = 23 g/mol; atomic weight of sodium.
M(Br) = 79.9 g/mol; atomic weight of bromine.
M(O) = 16 g/mol; atomic weight of oxygen.
M(Na) + M(Br) + M(O) = 23 g/mol + 79.9 g/mol + 16 g/mol.
M(Na) + M(Br) + M(O) = 118.9 g/mol, so compound is NaBrO and oxyanion is BrO⁻.
7 0
4 years ago
How are humans releasing carbon dioxide into the air?
Gekata [30.6K]

Answer: A minor but very important component of the atmosphere, carbon dioxide is released through natural processes such as respiration and volcano eruptions and through human activities such as deforestation, land use changes, and burning fossil fuels.

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5 0
4 years ago
How many moles of h2so4 are needed to neutralize 1.56 moles of koh?
Firlakuza [10]
The balanced equation for the above neutralisation reaction is as follows;
2KOH + H₂SO₄ --> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
neutralisation is the reaction between H⁺ ions and OH⁻ ions to form water which is neutral
number of KOH moles - 1.56 mol 
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0.78 mol of H₂SO₄ are required for neutralisation  
5 0
3 years ago
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