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3 years ago

12

Where is the temperate zone? A close to the equator B along bodies of water C next to the North and South Poles D between the po

lar and tropical zones

1 answer:

LenKa [72]3 years ago

5 0

Answer:

I think A close to the equator

You might be interested in

A buffer solution is prepared by adding NaC2H202

olganol [36]

Shift to reactants(left)

<h3>Further explanation </h3>

A buffer solution is a solution that can maintain a good pH value due to the addition of a little acid or a little base or dilution.

The buffer solution can be acidic or basic

Acid buffer solutions consist of weak acids and their salts.

A buffer solution of NaC2H202 and HC2H2O2 (acetic acid) is included in the acid buffer

So :

a slight addition of acid (H⁺) will be balanced by the conjugate base

the addition of a small base (OH⁻) will be balanced by the weak acid

With the addition of acid (H +), the equilibrium will shift to the left, in the formation of CH3COOH. The added acid will be neutralized by the conjugate base component (CH3COO−).

7 0

3 years ago

A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31

Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

$PV = nRT$

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

$n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles$

Now, we can find the temperature with the final conditions:

$T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K$

The temperature in Celsius is:

$T_{2} = 274.7 - 273 = 1.7 ^{\circ} C$

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!

8 0

3 years ago

New industrial plants for acetic acid react liquid methanol (Mm=32g/m) with carbon monoxide in the presen of a catalyst. In an e

Daniel [21]

Answer:

21.42 g

Explanation:

To know this, you need to put the equation that is taking and it's the following:

CH3OH (Methanol) + CO ---------> CH3COOH (Acetic acid)

We already know the mm of methanol, and the mm for CO is:

AM of C = 12 g/mol

AM of O = 16 g/mol

AM of H = 1 g/mol

MM of CO = 12 + 16 = 28 g/m

For acetic acid: 12 + 3(1) + 12 + 16*2 + 1 = 60 g/mol

Now that we know the molar mass of each molecule, let's calculate the number of moles of methanol and CO, because it's easier to work with moles than the grams

moles of methanol = 15/32 = 0.469 moles

moles of CO = 10/28 = 0.357 moles

According to the equation 1 mole of methanol reacts completely with 1 mole of CO. However, in this case, we can see that methanol exceed the CO, so, the CO is the limitant reactant so:

moles reactants of methanol: 0.469 - 0.357 = 0.112 moles.

moles of acid produced: 0.357 moles

This is because we have a ratio of 1:1 between methanol and CO. As methanol exceed CO, the CO is consumed completely leaving a remanant of methanol behind. the whole moles of CO are used, and appears as product of acetic acid, therefore, the moles of acetic acid are the same of CO.

Now with the molar mass of acid, let's calculate the gram of acid, and yield:

g = 0.357 * 60 = 21.42 g of acetic acid.

This is the theorical yield of acetic acid.

5 0

4 years ago

In order to change a solid to a liquid or a liquid to a gas, what is needed?

Neporo4naja [7]

Heat; rather, or change of the molecules to make them move faster

6 0

3 years ago

What do a mole of magnesium (Mg) and a mole of iron (Fe) have in common?

azamat

What they have in common is that they both have the same number of atoms.

9 0

3 years ago