<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
Answer:
Step-by-step explanation: I don't
8x^2+6x^2+4x=138 combine like terms on left side
14x^2+4x=138 since the number of seats in the from row is just 4x, subtract 14x^2 from both sides
4x=138-14x^2 that would be the general solution, if you wanted the actual number you would have to solve for x and then multiply that value by 4 to know what "4x" is...
14x^2+4x-138=0
14x^2-42x+46x-138=0
14x(x-3)+46(x-3)=0
(14x+46)(x-3)=0
2(7x+23)(x-3)=0, since x>0
x=3 and thus
4x=12 seats
So there are 12 seats in the front row addition.
using the formula:
y = mx +b
Using the given slope and coordinate points we get:
-1 = -3(2) + b
-1 = -6 + b
add 6 to each side
5 = b
y = -3x + 5
which is the same as:
3x + y = 5 ...answer choice a
