Which part of John Dalton’s theory was disproved by J.J. Thomson’s cathode-ray tube experiments?(1 point)

A box of table salt contains 737 g of NaCl. How many moles of NaCl are present in the box?

Oduvanchick [21]

The molecular weight of NaCl is 58.5 g/mol. 737 g/58.5 g/mol = 12.6 mol. So, there are 12.6 moles of NaCl in the box.

3 0

3 years ago

Consider the reaction a → b the rate of the reaction is 1.2 × 10−2 m/s when the concentration of a is 0.11 m. calculate the rate

kogti [31]

Dude im sorry but idk this one

8 0

4 years ago

Which method would increase the solubility of gas

jeka94

Answer:

BY increasing pressure and decreasing temperature.

Explanation:

The solubility of a gas increases with decrease in the temperature.

Also the solubility of a gas increases with increasing pressure.

A gas can be compressed by increasing the pressure and decreasing the temperature.

FOR example the gas in domestic LPG cylinders are in compressed form inside the cylinder.

A gas takes the form of a liquid after compressing. Whenever it comes back to normal temperature and pressure it takes back to its gaseous form back.

The gaseous oxygen is water soluble and does not react with it

O2 + 2H2O + 4 e= 4 OH-

4 0

3 years ago

Read 2 more answers

You start out with 800 moles of a radioactive substance. After 24 hours, 100 moles remain. What is the half-life of the substanc

Nookie1986 [14]

The half life of the substance is 8 hours , Option D is the correct answer.

What is Half Life ?

Half-life is the time required by an unstable element to reduce to half of its initial value.

The term is commonly used in nuclear physics.

The formula is

$\rm N(t) = \; N_{0} \;(\dfrac{1}{2} )^{\frac{t}{t_{1/2} } }$

N(t) = quantity of the substance remaining

N ₀ = initial quantity of the substance

t = time elapsed

$\rm t_{1/2}$ = half life of the substance

The data given in the question is N ₀ = 800 moles , N(t)= 100 , t= 24 hours

$\rm t_{1/2} =\; ?$

Substituting values in the equation

$\rm 100 = \; 800 \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }$

$\rm \dfrac{100}{800} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm \dfrac{1}{8} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm (\dfrac{1}{2})^{3} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm 3=\dfrac{24}{t_{1/2} }\\\\t_{1/2}= \dfrac{24}{3}\\\\t_{1/2} = 8 hours$