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NikAS [45]
3 years ago
6

This flow chart shows the amount of energy that is emitted by each type of light. ultraviolet > blue light > yellow light

> red light (maximum energy) (minimum energy) In an experiment, shining which type of light on a strip of metal would be least likely to produce the photoelectric effect?
Chemistry
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

the answer is red light

Explanation:

harina [27]3 years ago
3 0

Answer:

Explanation:

In photoelectric effect , radiation of some energy is made to fall on metal plate which results in the ejection of electrons by the metal plate . The kinetic energy of electrons comes from the energy of radiation falling on metal plate . Some of energy of radiation falling on metal plate is used in the process of bringing the  electron to  the surface and it is called threshold energy . The radiation must have at least this energy to see to it that electrons are ejected .  and the rest of the energy of radiation is used in imparting kinetic energy to the  electron .

The red light radiation has least energy so it is least likely to eject electrons from metal plate and produce photoelectric effect .

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What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml
Y_Kistochka [10]

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = \frac{5.50 g}{90 g/mol}=0.06111 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}

The molarity of the solution :

=\frac{0.06111 mol}{0.09766  L}=0.6257M

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

6 0
3 years ago
If you mix a 25.0mL sample of a 1.20m potassium sulfide solution with 15.0 mL of a 0.900m basium nitrate solution and the reacti
ddd [48]

Answer:

Limiting reagent: barium nitrate

Theoretical yield: 2.29 g BaS

Percent yield: 87%

Explanation:

The corrected balanced reaction equation is:

K₂S + Ba(NO₃)₂ ⇒ 2KNO₃ + BaS

The amount of potassium sulfide added is:

(25.0 mL)(1.20mol/L) = 30 mmol

The amount of barium nitrate added is:

(15.0mL)(0.900mol/L = 13.5 mmol

Since the reactant react in a 1:1 molar ratio, barium nitrate is the limiting reagent. If all of the limiting reagent reacts, the amount of barium sulfide produced is:

(13.5 mmol Ba(NO₃)₂)(BaS/Ba(NO₃)₂ ) = 13.5 mmol BaS

Converting this amount to grams gives the theoretical yield of BaS (molar mass 169.39 g/mol).

(13.5 mmol)(169.39 g/mol)(1g/1000mg) = 2.29 g BaS

The percent yield is calculated as follows:

(actual yield) / (theoretical yield) x 100%

(2.0 g) / (2.29 g) x 100% = 87%

6 0
3 years ago
Please someone help me Balance this equation.
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7 0
3 years ago
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Answer:

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3 years ago
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