Answer:
Explanation:
Given that:
The argon atoms are excited into an excited state before emitting the 488.0 nm laser.
the energy of the first ionization energy of argon is 1520 kJ mol-1.
SInce 1 eV = 96.49 kJ/mol
Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV
= 15.75 eV
To find where the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.
![E = \dfrac{hc}{\lambda}](https://tex.z-dn.net/?f=E%20%3D%20%5Cdfrac%7Bhc%7D%7B%5Clambda%7D)
![E = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{488 \times 10^{-9}}](https://tex.z-dn.net/?f=E%20%20%3D%20%5Cdfrac%7B6.6%20%5Ctimes%2010%5E%7B-34%7D%20%5Ctimes%203%20%5Ctimes%2010%5E8%7D%7B488%20%5Ctimes%2010%5E%7B-9%7D%7D)
![E = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}](https://tex.z-dn.net/?f=E%20%20%3D%20%5Cdfrac%7B1.98%20%5Ctimes%2010%5E%7B-25%7D%7D%7B488%20%5Ctimes%2010%5E%7B-9%7D%7D)
![E = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}](https://tex.z-dn.net/?f=E%20%20%3D%20%5Cdfrac%7B1.98%20%5Ctimes%2010%5E%7B-25%7D%7D%7B488%20%5Ctimes%2010%5E%7B-9%7D%7D)
![E =4.057 \times 10^{-19} \ J](https://tex.z-dn.net/?f=E%20%20%3D4.057%20%5Ctimes%2010%5E%7B-19%7D%20%5C%20J)
Converting Joules (J) to eV ; we get,
![E =\dfrac{4.057 \times 10^{-19}}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=E%20%20%3D%5Cdfrac%7B4.057%20%5Ctimes%2010%5E%7B-19%7D%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
E = 2.53 eV
The energy levels of the first exited state = -13.223 eV
Answer:
4.10x10⁻³g.
4.10 mg.
Explanation:
Hello,
In this case, considering the given number, we can see it has two digits after the first nonzero digit that is four (4) which is also at the third decimal place, it means that the scientific notation has a negative power as it is at the left of the given zeros, therefore it is:
4.10x10⁻³g.
Moreover, since the proper prefix for the factor x10⁻³ is milli, the number with prefix is:
4.10 mg.
Best regards.
Some physical property's that describe how something feels is texture.
Answer:
C
Explanation:
Charles law states that volume of gas is directly proportional to temperature at constant pressure
V/T = k
where V - volume , T - temperature and k - constant
\frac{V1}{T1} = \frac{V2}{T2}
T1
V1
=
T2
V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
in the question it states that the temperature has been increased from 278 K to 231 K but it should actually be temperature is decreased from 278 K to 308 K
substituting the values in the equation
\frac{417cm^{3} }{278K} = \frac{V}{308 K}
278K
417cm
3
=
308K
V
V = 462 cm³
the answer should be C. 462 cm³
Hey there!
Cr₄(P₂O₇)₃
Cr: 4 x 51.996 = 207.984
P: 6 x 30.97 = 185.82
O: 21 x 16 = 336
-------------------------------------
729.804 g/mol
The molar mass of Cr₄(P₂O₇)₃ is 729.804 g/mol.
Hope this helps!