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Ksju [112]
4 years ago
11

Please help with 48!

Chemistry
1 answer:
natima [27]4 years ago
4 0
A granite catches fire more quickly
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What is the wavelength of a 2500 kg truck traveling at a rate of 75km/h?
Pepsi [2]

m = mass of the truck traveling = 2500 kg

v = speed of the truck traveling = 75 km/h = 75 (km/h) (1000 m/ 1 km) (1 h /3600 sec) = 20.83 m/s

h = plank's constant = 6.63 x 10⁻³⁴

λ = wavelength of truck = ?

according to de broglie's principle, wavelength of truck is given as

λ = h/(mv)

inserting the values in the above equation

λ = (6.63 x 10⁻³⁴)/((2500) (20.83))

λ = 1.3 x 10⁻³⁸ m

5 0
3 years ago
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What is the molar mass for MgO?
podryga [215]

Answer:

40.3044 g/mol

Explanation:

4 0
3 years ago
Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio fr
Nataly_w [17]

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

  • The molar mass of K₂C₂O₄ is 184.24 g/mol.
  • The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4}  \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Learn more: brainly.com/question/15288923

7 0
3 years ago
how do i word a formal letter to a teacher saying i didn't pay attention during the science lessons and i now have no idea what
Allushta [10]

Explanation:

Hello mr/mrs (name) I unfortunately couldn't pay attention to the class due to some issues I had therefore I don't know what we are doing in class

OR

Hello mr/mrs (name) I could understand what we were doing in class I would like it if you could break it down more or explain better to me

OR just say something it had something to do with your internet such as

Hello mr/mrs (name) I didn't understand what you were saying during our class due to some of my internet issues I was have throughout the day. I hope you can explain what we did during the class.

Those may be some of my excuses I've used before

they have worked for me:)

I don't know if that helped?:/

8 0
3 years ago
The old car left on the side of the road showed signs of corrosion. We call this common chemical reaction rusting. The equation
Alex73 [517]
The answer is C) iron and oxygen. The reactants are on the left side of the equation
6 0
4 years ago
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