Answer:
When an electric current is passed through acidified water, it decomposes to give hydrogen and oxygen gas. The hydrogen gas is obtained at the cathode and the oxygen gas is obtained at the anode
Answer:
8.75 g of ZnO
Solution:
The Balance Chemical Reaction is as follow,
2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂
Step 1: Find out the limiting reagent as;
According to Equation ,
194.94 g (2 mole) ZnS reacts with = 96 g (3 moles) of O₂
So,
12.85 g of ZnS will react with = X g of O₂
Solving for X,
X = (12.85 g × 96 g) ÷ 194.94 g
X = 6.32 g of O₂
It means for total utilization of 12.85 g of ZnS we require 6.32 g of O₂, but we are provided with 15.91 g of O₂. Therefore, ZnS is the limiting reagent and will control the yield.
Step 2: Calculate Amount of ZnO produced as;
According to Equation ,
194.94 g (2 mole) ZnS produces = 132.81 g (2 moles) of ZnO
So,
12.85 g of ZnS will produce = X g of ZnO
Solving for X,
X = (12.85 g × 132.81 g) ÷ 194.94 g
X = 8.75 g of ZnO
Releases heat
(Exothermic)
Answer:
So if this is about chemical equations. You have 3 steps.
Step 1.- Count each type of atom in reactants and products.
Step 2.- Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.
Step 3.-Repeat steps 1 and 2 until the equation is balanced.
Explanation:
The answer is C. <span>The density of the fluid is greater than the density of the object.</span>