F(x) = 4x - 1
g(x) - 2x² + 3
<u>(f · g)(x)</u>
(f · g)(x) = (4x - 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) - 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) - 1(2x²) - 1(3)
(f · g)(x) = 8x³ + 12x - 2x² - 3
<u>(f/g)(x)</u>
(f/g)(x) = <u>4x - 1</u>
2x² + 3
<u>(g/f)(x)</u>
(g/f)(x) = <u>2x² + 3</u>
4x - 1
(g/f)(x)= ¹/₂x + ¹/₈ + <u> 3¹/₈ </u>
4x - 1
Answer:
41.5 units
Step-by-step explanation:
Given the data :
Month : J F M A M J J A S O N D
Inflow : 3 4 5 3 4 10 28 17 7 6 3 2
Outflow : 7 8 7 11 6 8 21 12 5 4 5 9
The unit of water in reservoir at the middle of August :
Initial unit = Unit of water at the start of the year = 50
Middle of August :
Inflow = 17 /2 = 8.5
Outflow = 12 /2 = 6
Unit of water at the middle of August :
Initial unit + Inflow - Outflow
Inflow till mid-August = (3+4+5+3+4+10+28+8.5) = 65.5
Outflow till mid-August = (7+8+7+11+6+8+21+6) = 74
50 + 65.5 - 74 = 41.5
F(x) = 5x - 6 and g(x) = x^2 - 5x + 6
(f - g)(x) = 5x - 6 - x^2 + 5x - 6 = -x^2 + 10x - 12
(f - g)(x) = -x^2 + 10x - 12
Answer:
Hi myself Shrushtee.
Step-by-step explanation:
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