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Neporo4naja [7]
3 years ago
9

Help...........................​

Mathematics
2 answers:
ipn [44]3 years ago
3 0

Answer:

If the answer helps you PLEASE mark me as brainliest

polet [3.4K]3 years ago
3 0

You can reformulate the expression in a more easier way, by using the concept of fraction. And so you get :

\frac{55}{11(\frac{120}{2*(4+(10+5-7)} )} =\frac{55}{11(\frac{120}{2*(12)} )}=\frac{55}{11(\frac{120}{24} )}=\frac{55}{11*5}  = \frac{55}{55} =1

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If ru is an altitude of rst find rs
Anna11 [10]

Answer:

The correct answer is Option D. 20

Step-by-step explanation:

From the figure we get,

<RUS = 90° because RU ⊥ TS

<u>To find the value of x</u>

It is given that <RUS = 4x + 54

Therefore we can write,

4x + 54 = 90

4x = 90 - 54 = 36

x = 36/4 = 9

<u>To find RS</u>

It is given that,

RS = 3x - 7 = 3*9 -7 = 20

Therefore the correct option is Option D . 20


4 0
3 years ago
Help me please with this
prisoha [69]
To factor this collect the like terms..2y would go with -7y to make -5y etc. Then factor the expression by factoring out 9 Your final answer should be 9(1-y+x^2)

If you need to simplify this calculate the sum or difference between numbers (3-1+7=9)
Your final answer for this should be 9-9y+9x^2

Hope this helps!
6 0
3 years ago
A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
What is the solution to 3x + 7 &lt; 19? x &lt; 4 x &gt; 4 x &lt; 12 x &gt; 12
Lana71 [14]
X<12 with a line underneath.
6 0
2 years ago
Read 2 more answers
How much does the 6 cats weights in pounds.
maksim [4K]
Add them all up and divide 6 (the number of terms given). The answer is 9.66 or 9.7 rounded to the nearest tenth.
8 0
3 years ago
Read 2 more answers
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