$1.40 - price from a supplier = 100%
100% + 80% = 180% = 1,8 - the retail price
1,40 * 1,8 = $2,52 - the retail price
100% - 25% = 75% = 0,75 - on sale for 25% off
2,52 * 0,75 = $1,89 - the sale price.
Answer:
Step-by-step explanation:
Move all terms to one side
4x^2 + 4x + 5 = 0
Plug into quadratic formula
x = (-4 <u>+</u>
) / 2(4)
= (-4 <u>+</u>
)/8
At this point, there are no real answers. The roots to this equation are complex.
x = (-4 <u>+</u> 8i)/8
= (-1 <u>+</u> 2i)/2
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
3<em>x</em> + 120° + <em>x</em> + 120° = 360°
4<em>x</em> + 240° = 360°
4<em>x</em> = 120°
<em>x</em> = 30°
<em>y</em> = 1/2 (3<em>x</em> - <em>x</em>)
<em>y</em> = 1/2 (90° - 30°)
<em>y</em> = 1/2 × 60°
<em>y</em> = 30°
Learned this yesterday, lol.
It's basically just:
100[ (33-24)/24 ]
100[ 9/24 ]
100[ 0.375 ]
37.5%