Answer:
Vertex: The common end point at which the two rays meet to form an angle is called the vertex. Here, the point O is the vertex of ∠AOB. We can find angles in various things around us, such as in a pair of scissors, a hockey stick, a chair.
Answer:
2nd choice:
x int: 11/6
y int: 11/2
Step-by-step explanation:
put 6x + 2y = 11 into y = mx+b form to find y intercept. (b stands for the y int)
you get y = -3x + 11/2.
now you can graph with this.
plug 0 in for y and solve for x to find x int
0 = -3x + 11/2 then solve
Answer: Okay! Here is your answer!
Exact form : 41/6
Decimal form : 6.83 (line over the 3)
Mixed number form : 6 5/6
Step-by-step explanation: Substitute the value of the variable into the equation and simplify.
Hope this is what you were looking for and I hope it helps you out! ☺
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units