Answer:
Percent ionic character is defined as the ratio of a bond’s actual dipole moment to the dipole moment it would have if the electron were completely transferred from one atom to the other, multiplied by 100
Explanation:
The percent ionic character seeks to establish the amount of electrovalency in a particular compound. It simply compares the covalency i.e extent of shared electrons to the the electrons that are transferred.
It is given as the ratio of the acutal dipole moment to the dipole moment due to ionic character of the bond multiplied by 100:
Percent ionic character = μ_obs/μ_ionic x 100
Where μobs is the actual dipole moment and μ ionic is the dipole moment if the bonds were 100% ionic.
The correct match is as follows:
Pressure and heat - Metamorphic rock
Cooling magma - The Intrusive igneous rock
Cooling lava - The Extrusive igneous rock
Erosion and Deposition - Sedimentary rock
This is because Metamorphic rocks are formed as a result of past existing rocks changing form. If the igneous and sedimentary rocks are exposed to high temperature and pressure, they then become metamorphic rocks.
Intrusive igneous rocks form when magma cools slowly. This process soon results in the formation of large-crystal like structures. Whereas, when exposed to the atmosphere lava cools rather quickly. This faster cooling process forms extrusive igneous rocks. The fast cooling lava creates smaller crystals and a smoother surface.
The sediments that are formed as a result of weathered rocks are usually deposited on the surface of Earth, or at the bottom of rivers and oceans. Over time, sediments collect and form layers over the most recent layer. This leads to the formation of sedimentary rocks.
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This is a question about the colligative property known as freezing point depression. Freezing point depression (the amount the normal freezing point of the solvent is decreased) can be calculated with this equation:
ΔT = i Kf<span> m
</span>
Where i (the van't Hoff factor) is the degree of dissociation of the solute, Kf is the freezing point depression constant, and m is the molality of the solution.
Here i = 2 (KCl dissociates into 2 ions, K+ and Cl-), Kf = 1.86 C/m (for water), and m = 0.743m).
ΔT = 2 x 1.86 C/m x 0.743m = <span>2.764C
</span>
That means the freezing point of the solution is 2.764C less than the pure solvent (water), making it 0C - 2.764C = -2.764C.
By the number group...... In the last shell
Answer:
When work is done on an object, the object gains energy
Explanation: