How many grams of CaCl2 are in .48 moles?
1 answer:
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Answer:
28500 years
Explanation:
Applying,
A = A'()............... Equation 1
Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.
From the question,
Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.
Substitute these values into equation 1
1 = 0.0313()
= 1/0.0313
= 31.95
≈ 32
≈ 2⁵
Equating the base and solve for x
x/5700 ≈ 5
x ≈ 5×5700
x ≈ 28500 years
Complete Question
Questions Diagram is attached below
Answer:
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Explanation:
From the question we are told that:
Temperature
Pressure
Volume
Generally the equation for gas Constant is mathematically given by
Therefore
Work-done
Generally the equation for internal energy is mathematically given by
Therefore
