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astraxan [27]
3 years ago
8

How many grams of CaCl2 are in .48 moles?

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

110.984 grams

Explanation:

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Select the correct answer from each drop-down menu.
Alika [10]

Answer:

Explanation:

There are three fundamentally known states of matter save for plasma and the Bose-Einstein condensate. These states of matter are solid, liquid and gas.

We can classify nearly all matter into these discrete categories based on certain lucid characteristics they exhibit.

  • Solids have definite shape and volume and they exhibit by the far the most remarkable internal ordering. Their molecules are attached by strong internal forces.
  • Liquids do not have a definite shape but takes the shape of the contains that hold them. They are not random and have internal cohesion among them.
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3 years ago
_______ are white blood cells that recognize specific antigens, and ultimately destroy them.
Lelu [443]

Answer:

Lymphocytes

Explanation:

Pathogens are particles that make you sick like bacteria, viruses, amoebas. Water is essential for life but that's for metabolism, not fighting off against infection or viruses.

4 0
3 years ago
Read 2 more answers
6.) The bond between which two atoms is most polar?*
Feliz [49]

Answer:

O-H bond

Explanation:

Let us work out the electronegativity difference between the elements in each bond in order to decide which of them is most polar.

For the C-O bond

2.55 - 2.2 =0.35

For the F-F bond

3.98 - 3.98 = 0

For the O-H bond

3.44 - 2.2 = 1.24

For the N-H bond

3.04 - 2.2 = 0.84

The O-H bond has the highest electronegativity difference, hence it is he most polar bond.

4 0
2 years ago
What was ernest rutherfords experiment
ohaa [14]

Answer: he shot tiny alpha particles throug a piece of gold foil.

Explanation:

6 0
3 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
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