Answer:
Final energy will be 40 KJ
Explanation:
We have given that 30 KJ of the heat is transferred to the water
So
And 5 KJ of heat is lost to the surrounding air
So
So total heat
The paddle-wheel work amounts to 5000 N -m
So work done W = -5 KJ ( as work is done by the paddle wheel )
We know that
We have given initial kinetic energy = 10 KJ
So
So final energy = 30+10 =40 KJ
Answer:
17.63W
Explanation:
The total energy supplied to the ice is used to melt the ice. Since the ice starts to melt at and also melts completely at the same temperature, the latent heat of fusion will be the focus in solving this problem.
Latent heat of fusion is defined as the amount of energy that changes a solid substance to liquid state without any change in temperature. It is given by the following relationship;
where m is the mass of the substance and l is the specific latent heat of fusion of the substance.
The specific latent heat of fusion of ice is approximately.
The total heat supplied to the ice was used to melt the ice and is calculated using equation (1), given that m = 4.56kg.
The total energy supplied to the ice is equivalent to the average power P entering the ice multiplied by the time t for which the power is supplied. Therefore;
where t = 1 day and 1 day = 24 hours.
24 hours = 60 x 60 x 24s =86400s.
Hence, t = 86400s.
Substituting into equation (2), we get the following;
Answer:
45 takes less energy and is less stronger light than a 60 watt bulb, but a 60 watt bulb is stronger and takes more energy.
Explanation:
Explanation:
The concentration of salt after t minutes is given by :
A tank contains 9000 L of pure water. Brine that contains 40 g of salt per liter of water is pumped into the tank at a rate of 25 L/min.
We need to find the concentration approach at
So,
Put
Since,
C(t) = 40 g/L
So, at the concentration approaches to 40 g/L. Hence, this is the required solution.
Work done by gravity = 23,520 J = mgh. Therefore m= 23520/ 30 x 9.8 = 80 kg.