In mechanics, the normal force<span> is the component, perpendicular to the surface (surface being a plane) of contact, of the contact </span>force<span> exerted on an object . We calculate as follows:
</span>∑F along x = 0 = F - Fn
<span>
Fn = F = mg = 7.52(9.81) = 73.77 N <------OPTION B</span>
Answer:
N = 19.6 N
Explanation:
Given that,
Mass of a block, m = 2000 g
1 kg = 1000 g
It means, 2000 g = 2kg
We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :
N = mg, g is acceleration due to gravity
N = 2 kg × 9.8 m/s²
N = 19.6 N
So, the normal force acting on the block is 19.6 N.
Ball will hit the ground after a time of 1.296 s
Explanation:
initial velocity of ball= Vi=0
g= 9.8 m/s²
height =h= 27 ft=8.23 m
using the kinematic equation
h= Vi t + 1/2 gt²
8.23=0(t) + 1/2 (9.8)t²
t²=1.6796
t=1.296 s
