Answer:
# = 6.6 10¹⁵ electrons for r = 1 m
# = 6.6 10¹³ electrons for r= 1 cm
Explanation:
The electric force is given by Coulomb's law
F = k q₁ q₂ / r²
Where k is the Coulomb constant that is worth 8.99 10⁹ N m²/C², q are the charges and r the distance between them.
Let's apply this equation to our case. Initially the spheres are not attracted so the net charge in each of them is zero, removing electrons in one of them is a positive net charge of equal value to the negative charge removed. The specific answer of this exercise depends on the distance of the two spheres, by calculation we assume that it is 1 m
The charge of an electron is q₀ = -1.6 10⁻¹⁹ C, the total charge is
q = #_electron q₀
F = k # q₀ # q₀ / r²
#² = F r² / k q₀²
# = √ F r² / k q₀²
Let's calculate for r = 1 m
# = √ [1 10⁴ 1 / 8.99 10⁹ (1.6 10⁻¹⁹)²]
# = √ [43.45 10³⁰]
# = 6.6 10¹⁵ electrons for r = 1 m
If the distance is reduced to r = 1 cm = 1 10⁻² m
The number of electrons is reduced to
# = 6.6 10¹³ electrons
Answer:
i. 6.923 V
ii. The e.m.f. = 22.5 V
Explanation:
i. The given parameters are;
Length of potentiometer = 1 m
The resistance of the potentiometer = 10 Ω
The e. m. f. of the attached cell = 9 V
The current, I flowing in the circuit = e. m. f/(Total resistance)
The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A
The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire
The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V
ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;
Where:
E = e.m.f. of the balance point cell
= Resistance of 75 cm of potentiometer wire = 0.75×10 = 7.5 Ω
= Resistance of the cell in the circuit = 3 Ω
V = e.m.f. attached cell = 9 V
E = 7.5*3 = 22.5 V
The e.m.f. = 22.5 V
Increasing speed, decreasing speed, or a change in direction
The difference in height between the ground floor and the third floor is
<h3>What is gauge pressure?</h3>
The pressure measured by the pressure gauge is called the gauge pressure.
Given is the the pressure in a water pipe in the ground floor of a building is 4×10⁵ Pa and three floors up is 2×10⁵ Pa. Density of water ρ = 1×10³ kg/m³
From the Bernoulli's theorem,
ΔPg = ρgΔh
( 4×10⁵ - 2×10⁵) = 1000 x 9.81 x Δh
Δh = 20.4 m
Thus, the difference in height is 20.4 m
Learn more about gauge pressure
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