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nydimaria [60]
3 years ago
9

Determine if the conjecture is true or false. If true, explain your reasoning briefly. If false provide a counterexample.

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

9514 1404 393

Answer:

  false

Step-by-step explanation:

The conjecture shown in this problem statement does not follow from the examples offered. They support the notion that ...

  1/x ≤ x . . . . for x ≥ 0 (<u>not x ≤ 0</u>)

There are several possible counterexamples showing the conjecture is FALSE.

  1. 1/0 is undefined
  2. 1/(-5) > -5 . . . . . . . . a case for x < 0

If the intended domain is x ≥ 0, then the conjecture can also be demonstrated to be false for 0 < x < 1:

  1. 1/(1/5) > 1/5
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Step-by-step explanation:

This is the answer because that is the only thing in the options higher than Keisha's expression.

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Step-by-step explanation:

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Molodets [167]

Answer:

8x^8/3 y^4 - The first option

Step-by-step explanation:

The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.

This means that the expression is now:

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First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3

The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.

So now our expression is:

8(x^8/3 y^4)

Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:

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3 years ago
Read 2 more answers
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