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Liula [17]
3 years ago
14

Which of the following has to happen before the eardrum begins to vibrate with the same frequency as the source of the sound wav

es? A. Vibrations have to be transmitted to the fibers of the auditory nerve. B. The brain has to interpret the direction from which the sounds are being delivered. C. Impulses have to be sent to the brain through the auditory nerve. D. The outer ear has to collect the sound waves and lead them to the middle ear.
Physics
2 answers:
777dan777 [17]3 years ago
8 0
I just took the test it is D




I am 100% sure
Sladkaya [172]3 years ago
6 0

Answer:

D. The outer ear has to collect the sound waves and lead them to the middle ear.

Explanation:

Here when sound propagates through air then first the sound is collected by the outer part of the ear.

then it is propagated to the middle ear and then this will hit the ear drum situated at the inner ear.

Then this vibrations received on the inner part of year is converted into electrical signals and carried by the nerves to the brain.

then brain interpret these signals into sound

So here we will have

D. The outer ear has to collect the sound waves and lead them to the middle ear.

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An object of known mass M with speed v0 travels toward a wall. The object collides with it and bounces away from the wall in the
Bingel [31]

Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision

Explanation:

The impulse theorem states that the change in momentum of an object is equal to the impulse, which is the product between the average force applied and the duration of the collision:

\Delta p = F \Delta t

where

\Delta p is the change in momentum

F is the average force

\Delta t is the duration of the collision

In this problem, neither side of the equation can be used to measure the change in momentum. In fact:

- The change in momentum (left side) is given by

\Delta p = m(v-u)

where

m is the mass of the object

u is the initial velocity

v is the final velocity

Here the final velocity is not known, so it's not possible to use this side of the equation

- The impulse (right side) is given by

F\Delta t

here the average force is known, however the duration of the collision is not known, so it's not possible to use this side of the equation.

Learn more about momentum:

brainly.com/question/9484203

#LearnwithBrainly

3 0
3 years ago
a force is applied to a box of 10.0 kg for 4.0 s. the box goes from rest to 25 m/s in that time. What is the magnitude of that f
Paul [167]

Given:

m(mass of the box)=10 Kg

t(time of impact)=4 sec

u(initial velocity)=0.(as the body is initially at rest).

v(final velocity)=25m/s

Now we know that

v=u+at

Where v is the final velocity

u is the initial velocity

a is the acceleration acting on the body

t is the time of impact

Substituting these values we get

25=0+a x 4

4a=25

a=6.25m/s^2

Now we also know that

F=mxa

F=10 x6.25

F=62.5N

8 0
4 years ago
A vector has an x component of 25.0 units and a y
sammy [17]
Here is the answer to your question

8 0
3 years ago
What type of image can a convex mirror produce?
Digiron [165]
Convex mirrors only produce virtual images
7 0
4 years ago
Read 2 more answers
You observe two cars traveling in the same direction on a long, straight section of Highway 5. The red car is moving at a consta
Romashka-Z-Leto [24]

Answer:

a) 3.66 s

b) 124.4 m

c) 3.12s

Explanation:

Given that

Speed of the Red Car, v₁ = 34 m/s

Speed of the Blue Car, v₂ = 28 m/s

Distance between the two cars, d = 22 m

The difference between the speed of the cars is: 34 - 28 = 6 m/s

From this, we can deduce that the red car will be catching up to the blue car at a speed of 6 m/s.

1)

If we divide the distance by the difference in speed. This becomes

d/v = 22/6 = 3.66 s. Which means, It takes 3.66 seconds for the red car to meet up with the blue car.

2

From the previous part, we were able to confirm that it took 3.66 seconds for the red car to meet up the blue car. Also, the speed with which it were traveling was travelling at, was constant, so we only need to multiply it by the time from (1) to get the distance.

v = d * t = 34 * 3.66 = 124.4

Therefore the red car travels at 124.4 m before catching up to the blue car.

3

If the red car starts to accelerate the moment we see it, the time it will take, to get to the blue car will be less than what we had gotten. We can find this using one of the equations of motion.

S = ut + ½gt², where

S = 22

u = 6

t = ?

g = 2/3

22 = 6t + 1/3t²

By using the quadratic formula, we find out the two answers listed below

t1 = 3.12 s

t2 = - 21.12 s

We all know that negative time is not possible, so the answer is t1. At 3.12 seconds

8 0
3 years ago
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