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Phantasy [73]
3 years ago
6

A person looks across a stadium at the scoreboard, which appears blurry. The person looks down at the program, which is complete

ly in focus. What vision condition is described?
a) color blindness

b) astigmatism

c) farsightedness

d) nearsightedness
Physics
2 answers:
Alecsey [184]3 years ago
5 0

Answer:

d) nearsightedness

Explanation:

Nearsightedness (myopia) is a common vision condition in which you can see objects near to you clearly, but objects farther away are blurry. It occurs when the shape of your eye causes light rays to bend (refract) incorrectly, focusing images in front of your retina instead of on your retina

Pepsi [2]3 years ago
3 0
Answer is D. Nearsightedness is when a person can see near, but not far. Everything appears blurry from far away, but as you get close to it, it becomes more focused
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A bird flies from the South Pole to the North Pole. Part of the journey is 1000 miles that takes 2 weeks. What is the bird’s vel
viktelen [127]
1000 miles = 1610km = 1.61x10^6m
2 weeks = 14 days = 14x24x1440

V=d/t = 1.61x10^6/14x24x1440
= 3.33m/s
6 0
3 years ago
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A vertical spring with a spring constant of 420 N/m is mounted on the floor. From directly above the spring, which is unstrained
mixas84 [53]

Answer:

19.53 cm

Explanation:

The computation of the height is as follows:

Here we applied the conservation of the energy formula

As we know that

P.E of the block = P.E of the spring

 m g h = ( 1 ÷ 2) k x^2

where

m = 0.15

g = 9.81

k = 420

x = 0.037

So now put the values to the above formula

(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2

1.4715 (h) = 0.28749

h = 0.19537 m

= 19.53 cm

3 0
2 years ago
What is the speed of a car that traveled 500 meter in 30 seconds?
GenaCL600 [577]
<h2>Greetings!</h2>

To find speed, you need to remember the formula:

Speed = distance ÷ time

So plug the given values in:

500 ÷ 30 = 16.66

<h3>So the speed is 16.66m/s (metres per second)</h3>
<h2>Hope this helps!</h2>
3 0
3 years ago
An object accelerates in a direction that is always perpendicular to its motion.
anzhelika [568]
The object will not be able to accelerate perpendicular to direction of motion
7 0
3 years ago
A child's top is held in place upright on a frictionless surface. The axle has a radius of ????=3.21 mm . Two strings are wrappe
tekilochka [14]

Answer:

Angular momentum, L=6.47\times 10^{-3}\ m

Explanation:

It is given that,

Radius of the axle, r=3.21\ mm=3.21\times 10^{-3}\ m

Tension acting on the top, T = 3.15 N

Time taken by the string to unwind, t = 0.32 s

We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

\tau=\dfrac{dL}{dt}

Torque acting on the top is given by :

\tau=F\times r

Here, F is the tension acting on it. Torque acting on the top is given by :

\tau=2F\times r

2T\times r=\dfrac{L}{t}

L=2T\times r \times t

L=2\times 3.15\times 3.21\times 10^{-3}\times 0.32

L=6.47\times 10^{-3}\ m

So, the angular momentum acquired by the top is 6.47\times 10^{-3}\ m. Hence, this is the required solution.

7 0
3 years ago
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