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AVprozaik [17]
3 years ago
11

Explain what is meant by “field” and compare the properties of gravitational, electric, and magnetic forces in terms of particle

s affected, factors affecting the magnitude, and their relative strengths.
Physics
1 answer:
notsponge [240]3 years ago
6 0
Field in this context refers to a region of the space to which corresponds a value.

There is a gravitational field around the earth, because a mass m placed at any point around the earth will be atracted (gravitational force) by it.

There is an electric field in a point when a charge placed there feels an electric force.

The gravitational field is proportional to the value of the mass of the object that produces it.

The electric field is proportional to the magnitude of the charge of the particle that produces it.

The gravitational field is always attractive. The electric field may be attractive or repulsive.

Both fields are proportional to the inverse of the squared distance.

The magnetic field is created when a charge is in movement,i.e a charge in movement will create a magnetid fiedl around it that will act and create a magnetic force over other charge also in movement.

The magnetic field is proportional to the product of the charge times its velocity and inversely proportional to the squared distance. The force generated my be attractive or repulsive.
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2 years ago
A 20-kg block is held at rest on the inclined slope by a peg. A 2-kg pendulum starts at rest in a horizontal position when it is
gregori [183]

Complete Question

The diagram of this question is shown on the first uploaded image

Answer:

The distance the block slides before stopping is d = 0.313 \ m

Explanation:

The free body diagram for the diagram in the question is shown

From the diagram the angle is \theta = 25 ^o

         sin \theta  = \frac{h}{d}

Where h = h_b - h_a

     So      d sin \theta  = h_b - h_a

From the question we are told that

      The mass of the block is  m = 20 \ kg

       The mass of the pendulum is  m_p = 2 \ kg

       The velocity of the pendulum at the bottom of swing is v_p = 15 m/s

        The coefficient of restitution is  e =0.7

         The coefficient of kinetic friction is  \mu _k = 0.5

The velocity of the block after the impact is mathematically represented as

            v_2 f = \frac{m_b - em_p}{m_b + m_p}  * v_2 i + \frac{[1 + e] m_1}{m_1 + m_2 } v_p

Where  v_2 i is the velocity of the block  before collision which is  0

                  = \frac{20 - (0.7 * 2)}{(2 + 20)} * 0 + \frac{(1 + 0.7) * 2 }{2 + 20}   * 15

Substituting value

                   v_2 f = 2.310\  m/s

According to conservation of energy principle

      The energy at point a  =  energy at point b

So    PE_A + KE _A = PE_B + KE_B  +  E_F

Where  

         PE_A is the potential energy at A which is mathematically represented as

          PE_A = m_b gh_a = 0 at the bottom

      KE _A is the kinetic energy at A  which is mathematically represented as

               K_A = \frac{1}{2} m_b * v_2f^2                  

         PE_B is the potential energy at B which is mathematically represented as  

            PE_B = m_b gh

From the diagram h = h_b -h_a

       PE_B = m_b g(h_b - h_a)

KE _B is the kinetic energy at B  which is 0 (at the top )

Where is E_F is the workdone against velocity  which from the diagram is

      \mu_k m_b g cos 25 *d

So

   \frac{1}{2} m_b v_2 f^2  = m_b g h_b + \mu_k m_b g cos \25 * d

Substituting values

   \frac{1}{2}  * 20 * 2.310^2 = 20 * 9.8 * d sin(25)  + 0.5* 20 * 9.8 * cos 25 * d    

So

       d = 0.313 \ m

       

   

6 0
3 years ago
How is the direction of light changed when it travels from an optically denser medium to an optically rarer medium????? please a
ANTONII [103]

Answer:

The light bends away from the normal

Explanation:

We can solve the problem by using Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where:

n_1 is the index of refraction of the first medium

n_2 is the index of refraction of the second medium

\theta_1 is the angle of incidence (angle between the incoming ray and the normal to the interface)

\theta_2 is the angle of refraction (angle between the outcoming ray and the normal to the interface)

We can rearrange the equation as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

In this problem, light travels from an optically denser medium to an optically rarer medium, so

n_1 > n_2

Therefore, the term \frac{n_1}{n_2} is greater than 1, so

sin \theta_2 > sin \theta_1\\\rightarrow \theta_2 > \theta_1

which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.

4 0
3 years ago
Los rieles de una vía de tren de acero tienen 1500 m de longitud. ¿Qué longitud tendrá cuando
melomori [17]

Answer:

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6 0
3 years ago
Two 20.0 g ice cubes at − 20.0 ∘ C are placed into 285 g of water at 25.0 ∘ C. Assuming no energy is transferred to or from the
Lelechka [254]

Answer:

Ft = 17.48°C

Explanation:

Ft is the final temperature. However, ice absorbs heat during two process of melting and cooling and as such, there is no loss of heat to or from the surrounding hence by conservation of energy.

Therefore,

Heat absorbed by water of 20g = heat rejected by water of 265g.

So; M(ice)[C(ice) [(ΔT) + LH(ice) + C(water)(ΔT)] = C(water) M(water) (ΔT)

So, 20[(2.108) [0 - (-20)] + 333.5 + 4.187(Ft - 0)]] = (285)(4.187) (25 - Ft)

To get;

7513 + 83.74 Ft = 29832.4 - 1193.3 Ft

So factorizing, we get;

83.74 Ft + 1193.3 Ft = 29832.4 - 7513

So; 1277.04 Ft = 22319.4

So; Ft = 22319.4/1277.04 = 17.48°C

7 0
3 years ago
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