Answer:
Magnitude of induced emf will be 
Explanation:
We have given radius of the circular loop r = 19.7 cm = 0.197 m
So area of the circular loop 
It is given that magnetic field is changing as 
Emf induced in the circular loop is equal to 
So emf induced will be equal to 
So magnitude of induced emf will be 
Answer:

Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

So, the acceleration of the car is
.
Answer:
1. G.P.E = 24 J
2. center of mass
Explanation:
Given the following data;
Mass = 2kg
Height, h = 1.2m
Acceleration due to gravity = 9.8 N/kg or m/s².
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;

Where;
- G.P.E represents potential energy measured in Joules.
- m represents the mass of an object.
- g represents acceleration due to gravity measured in meters per seconds square.
- h represents the height measured in meters.
Substituting into the formula, we have;

G.P.E = 23.52 to 2 S.F = 24 Joules.
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.
A) experiment. Is the answer.
hypothesis is the educated guess about what the result of the experiment is before conducting the experiment.
Observation is what you see and record during the experiment.
Answer:
51.94 ft/s²
257.63 ft/s
Explanation:
t = Time taken = 4 s
u = Initial velocity = 34 mi/h
v = Final velocity
s = Displacement = 615 ft
a = Acceleration
Converting velocity to ft/s

Equation of motion

Acceleration is 51.94 ft/s²

Final velocity at this time is 257.63 ft/s