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Mandarinka [93]
3 years ago
5

A certain corner of a room is selected as the origin of a rectangular coordinate system. If a fly is crawling on an adjacent wal

l at a point having coordinates (2.3, 1.2), where the units are meters, what is the distance of the fly from the corner of the room?
Physics
1 answer:
Helga [31]3 years ago
5 0

Answer:

2.59 m

Explanation:

Coordinates of origin = (0, 0)

Coordinates of Point p where the fly reach = (2.3 m, 1.2 m)

Use the distance formula of coordinates to find the distance between the origin and the point P.

d=\sqrt{\left ( x_{2}-x_{1} \right )^{2}+\left ( y_{2}-y_{1} \right )^{2}}

d=\sqrt{\left ( 2.3- 0 \right )^{2}+\left ( 1.2-0 \right )^{2}}

d = 2.59 m

Thus, the distance between the origin and the point P is 2.59 m.

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The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th
FrozenT [24]

0.74in

Explanation:

Given parameters:

length range of adult mosquito = 3.0 - 6.0mm

Smallest mosquito = 2.5mm

Largest mosquito = 19mm

Average mass range = 3.0 - 5.0mg

Unknown:

Length of largest known mosquito in inches = ?

Solution;

The length is the longest dimension. It is how long a body is.

 The problem here is converting from mm to inches;

 

The length of the longest mosquito which is the largest is 19mm

 19mm to inches;

     1mm = 0.039inches

  19mm = 19mm x \frac{0.039in}{1mm} = 0.74in

learn more:

Scale brainly.com/question/570757

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4 0
3 years ago
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Hoochie [10]

Answer:

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Explanation:

5 0
2 years ago
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How often is carbon dioxide cycled through the atmosphere
olga55 [171]

Maybe around 350 years, depending on the carbon cycle and the time taken through steps.

5 0
3 years ago
A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a
Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

m_1v_1+m_2v_2 = (m_1+m_2)V_f

Where,

m_{1,2}= Mass of each object

v_{1,2}= Initial Velocity of Each object

V_f= Final Velocity

Our values are given as

m_1 = 2190Kg

v_1 =10.5m/s

m_2 = 3220kg

V_f = 4.74m/s

Replacing we have that

m_1v_1+m_2v_2 = (m_1+m_2)V_f

(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)

v_2 = 0.8224m/s

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0
3 years ago
Convert 56 kilometers to inches
svlad2 [7]
The conversion for km to inches is:

1km=39370.1in

Now we can solve for 56 km..

56km=39370.1*56
56km=<span> 2204725.6in

Answer=2,204,725.6in</span>
7 0
3 years ago
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