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2 years ago

Exam for edmentum// multiplying monomials please help

Mathematics

1 answer:

Artemon [7]2 years ago

4 0

Answer:

$3 {w}^{5} \times {7w}^{5} \\ \\ = (3 \times 7)( {w}^{5} \times {w}^{5} ) \\ \\ = 21( {w}^{5} \times {w}^{5} )$

from law of indices:

${x}^{a} + {x}^{b} = {x}^{(a + b)}$

therefore:

$= 21 \{ {w}^{(5 + 5)} \} \\ \\ ={ \boxed{ 21 {w}^{10} }}$

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What compound inequality describes this graph?

katovenus [111]

Answer:

The answer to your question is 0 < x ≤ 3

Step-by-step explanation:

To write this inequality we must consider

- The value of the borders, for this inequality the borders are 0 and 3.

-The kind of border - if it is an open point, we will use the symbol <

- if it is a close c point, we will use the symbol ≤

-The inequality for this problem will be

0 < x ≤ 3

8 0

3 years ago

Can someone please help me with this graph question??? Please???

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Solution (8 , 9)

Answer is A. (8,9)

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3 years ago

As a result of a cyclone, the price of bananas rose 85% to $9.99 per kg. How much did bananas cost before the cyclone?

Karo-lina-s [1.5K]

The original price was $8.49 :)

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3 years ago

The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro

ra1l [238]

Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0

3 years ago

Please help me! in need of help due tomorrow!

julsineya [31]

Answer:

Step-by-step explanation:

(1). A = π r²

A = 4 π

Area of shaded region is $\frac{4\pi *260}{360}$ = $\frac{26}{9} \pi$ or $\frac{26\pi }{9}$