Question

Exam for edmentum// multiplying monomials please help

Answer 1

Answer:

$3 {w}^{5} \times {7w}^{5} \\ \\ = (3 \times 7)( {w}^{5} \times {w}^{5} ) \\ \\ = 21( {w}^{5} \times {w}^{5} )$

from law of indices:

${x}^{a} + {x}^{b} = {x}^{(a + b)}$

therefore:

$= 21 \{ {w}^{(5 + 5)} \} \\ \\ ={ \boxed{ 21 {w}^{10} }}$