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juin [17]
3 years ago
9

5. Two shelves are on a wall with one directly above the other. One shelf is 4 5/6 feet above the floor and the other is 5% 9/10

feet above the floor. Find the distance between the shelves.​
Mathematics
1 answer:
Levart [38]3 years ago
5 0
5 9/10 - 4 5/6 = (5x10+9)/10 - (4x6+5)/6 = 59/10 - 29/6 = 177/30 - 145/30 = 32/30 = 1 1/15 feet apart
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Please help I’m desperate
JulijaS [17]

Answer:

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There are five boys to every nine girls in an introductory engineering course .if there are 364 students enrolled in the course
Nadusha1986 [10]

Answer:

234

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3 0
3 years ago
I don't know how to do this but I know you have to find the growth or decay
xenn [34]

Answer:

\boxed{y=5(1.05)^t\to\:5\% \:rate \:of \:growth}

\boxed{f(t)=50(.95)^t\to\:5\% \:rate \:of \:decay}

\boxed{g(t)=50(1.5)^t\to\:50\% \:rate \:of \:growth}

\boxed{y=5(.5)^t\to\:50\% \:rate \:of \:decay}

Step-by-step explanation:

We can rewrite the given functions in the form f(x)=a(100\%+r\%)^x to determine the rate of growth or f(x)=a(100\%-r\%)^x to determine the rate of decay

y=5(1.05)^t=5(100\%+5\%)^t\to\:5\% \:rate \:of \:growth

f(t)=50(.95)^t=50(100\%-5\%)^t\to\:5\% \:rate \:of \:decay

g(t)=50(1.5)^t=50(100\%+50\%)^t\to\:50\% \:rate \:of \:growth

y=5(.5)^t=5(100\%-50\%)^t\to\:50\% \:rate \:of \:decay

4 0
4 years ago
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