The answer is : linea aspera
<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by
and
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh (
) =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh (
) will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6
Answer:
D. phospholipid bilayer
Explanation:
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When you combine the genotypes in the Punnet square you get :
1. EeRR
2.Eerr
3.EeRr
4.eerr
The ratio would be typical for a dihybrid cross: 9 of the individuals with both dominant traits, 3 of the individuals dominant for one trait, 3 dominant for the other trait and only one recessive for both traits.
There will be 9/16 of ebony flyes with red eyes
3-16 of ebony flies with orange eyes
3/16 of yellow flies with red eyes
1/16 of yellow flies with orange eyes
Explanation:
energy flows in only one direction through an ecosystem.