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3 years ago

15

3. Force = _ x _?

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

Explanation:

Force = mass * acceleration.

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State the term used to describe the turning force exerted by the man

ozzi

]A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever.

The way levers work is by multiplying the effort exerted by the user. Specifically, to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

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2 years ago

A basketball of mass 0.23kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a ve

Anna11 [10]

Answer:

$8.1\:\mathrm{Ns}$

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

$\Delta p = m\Delta v$ , where $m$ is the mass of the basketball and $\Delta v$ is the change in velocity.

Since the basketball is changing direction, its total change in velocity is:

$\Delta v = 20-(-15)=35\:\mathrm{m/s}$ .

Therefore, the basketball's change in momentum is:

$\Delta p = m\Delta v = 0.23\cdot 35= 8.05=8.1\:\mathrm{kg\cdot m/s}$ .

Thus, the impulse on the basketball is $\fbox{$8.1\:\mathrm{Ns}$}$ (two significant figures).

7 0

3 years ago

A solid steel column is 4.0 m long and 0.20 m in diameter. Young's modulus for this steel is 2.0 × 1011 N/m2. By what distance d

zzz [600]

Answer:

3.12 x 10^-5 m

Explanation:

Length of steel column, L = 4 m

diameter, d = 0.2 m

radius = half of diameter = 0.1 m

Young's modulus, Y = 2 x 10^11 N/m^2

Mass of truck, m = 5000 kg

Force, F = mass of truck x acceleration due to gravity

F = 5000 x 9.8 = 49000 N

Area of crossection of cable,

A = $\pi r^{2}=3.14\times\0.1\times0.1=0.0314m^{2}$

Let ΔL be the shrink in length of cable, then by the formula of Young's modulus

$Y=\frac{F\times L}{A\times\Delta L}$

$\Delta L = \frac{F\times L}{A\times Y}$

$\Delta L = \frac{49000\times 4}{0.0314\times 2\times10^{11}}$

ΔL = 3.12 x 10^-5 m

Thus, the shrink in the length of cable is 3.12 x 10^-5 m.

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3 years ago

A body of mass m moves along y such that at time t its position is y(t)= at^2 – bt + c, where a, b, c are constant.

Akimi4 [234]

Answer:

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Explanation:

A body of mass m moves along X-axis such that its position co-ordiante at any instant t is x = `at^(4)

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3 years ago

A student is pushing a box across the room. To push the box three times farther, the student needs to do how much work?

Marrrta [24]

D. Three times as much

7 0

3 years ago