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netineya [11]
3 years ago
15

3. Force = _____ x _____?

Physics
1 answer:
harkovskaia [24]3 years ago
8 0

Answer:

Explanation:

Force = mass * acceleration.

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A 2.40 kgkg can of coffee moving at 1.50 m/sm/s in the +x+x-direction on a kitchen counter collides head-on with a 1.20 kgkg box
Monica [59]

Answer:

1.35 m/s in the +x direction

Explanation:

Mass of can of coffee, m = 2.4 kg

Initial velocity of can of coffee, u = 1.5 m/s

Mass of box of macaroni, M = 1.2 kg

Initial velocity of box of macaroni, U = 0 m/s

Final velocity of can of coffee, v = 0.825 m/s

We can find the final velocity of the box of macaroni, V, by using the Principle of Conservation of momentum:

Total initial momentum = Total final momentum

Momentum is given as the product of mass and velocity. Hence:

mu + MU = mv + MV

(2.4 * 1.5) + (1.2 * 0) = (2.4 * 0.825) + (1.2 * V)

3.6 + 0 = 1.98 + 1.2V

1.2V = 3.6 - 1.98 = 1.62

=> V = 1.62/1.2

V = 1.35 m/s

The final velocity of the box of macaroni is 1.35 m/s and it is in the +x direction.

3 0
3 years ago
On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
Luda [366]

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

V_{avg} = \frac{Final \ position\  - \ Initial \ position}{final \ time\  - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\  - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr

Therefore, the average velocity is 180 km/hr

3 0
3 years ago
A typical tire for a compact car is 22 inches in diameter. If the car is traveling at a speed of 60 mi/hr, find the number of re
Softa [21]

Answer:

rpm= 916.7436 rev/min

Explanation:

First determine the perimeter of the wheel, to know the horizontal distance it travels in a revolution:

perimeter= π×diameter= π × 22 inches × 0.0254(m/inche)= 1.7555m

Time we divide the speed of the car, which is the distance traveled horizontally over time unit, by the perimeter of the wheel that is the horizontal distance traveled in a revolution, this dates us the revolutions over the time unit:

revolutions per time= velocity/perimeter

velocity= (60 mi/hr) × (1609.34m/mi) = 96560m/h

revolutions per time= (96560.6m/h) / (1.7555m)= 55004.614 rev/hr

rpm= (55004.614 rev/hr) × (hr/60min)= 916.7436 rev/min

3 0
4 years ago
A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re
forsale [732]

Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

(1) we solve for the  initial potential energy stored

Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

ΔV = mgh

=(0.1/9.8) * 9.8 * 1.5 = 0.15J

The internal energy = 0.2 -0.15

=0.05J

8 0
3 years ago
The fiugure below shows a birds eye view of ta car going around a highway curve
luda_lava [24]
Okay whats the question though?
5 0
4 years ago
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