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xenn [34]
3 years ago
12

What is a group of organs working together called

Biology
2 answers:
zhenek [66]3 years ago
5 0

Answer:Organ system

Explanation:

Deffense [45]3 years ago
5 0

Answer:

A System

Explanation:

I am 100% sure

cells \: > tissue >  \: organ > system > organism

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if a specimen takes up one quarter of the field of view (0.500 mm), what is the size of the specimen in micrometers (um)?
weeeeeb [17]
Gotta add so it can be right
4 0
3 years ago
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PI 3-kinase:_________
lana [24]

Answer:

The correct answer is - option A

Explanation:

Phosphoinositide 3-kinases or PI-3 kinse, are enzymes involved in essential cellular functions such as the growth of the cell, proliferation, motility, differentiation, survival and intracellular movement, which in turn are plays role in cancer.

PI3-kinase with oncogene PIK3CA and tumor suppressor PTEN, is implicated in the insensitivity of cancer tumors.

Thus, the correct answer is option A)

6 0
3 years ago
A geneticist crossed fruit flies to determine the phenotypic ratio. The geneticist crossed a fly with blistery wings and spinele
kondor19780726 [428]

Complete question:

A geneticist crossed fruit flies to determine the phenotypic ratio. The geneticist crossed a fly with blistery wings and spineless bristles (bbss) with a heterozygous fly that had normal wings and normal bristles (BbSs). Which proportion of offspring that are dominant for both traits in would you not expect based on Mendel's law of independent assortment? 1/2 , 4/16, 25% , or 1/4

Answer:

1/2 is the proportion of the offspring that is NOT expected among individuals that are dominant for both traits.

4/16 = 1/4 = 25% of the progeny and the correct expected proportion of individuals that are dominant for both traits.

Explanation:

<u>Available data</u>:

  • Cross:  a fly with blistery wings and spineless bristles with a heterozygous fly that had normal wings and normal bristles
  • Recessive trait: blistery wings and spineless bristles
  • Dominant trait: normal wings and normal bristles

Let us say that:

  • B is the dominant allele for normal wings
  • b is the recessive allele for blistery wings
  • S is the dominant allele for normal bristles
  • s is the recessive allele for spineless bristles

Parentals)        bbss       x        BbSs

Gametes)  bs, bs, bs, bs     BS, Bs, bS, bs

Punnett square)    BS        Bs         bS        bs

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

F1)  4/16 = 1/4 = 25%  of the progeny is expected to be BbSs, dyhibrid individuals, expressing normal wings and normal bristles

     4/16 = 1/4 = 25% of the progeny is expected to be Bbss, expressing normal wings and spineless bristles

     4/16 = 1/4 = 25% of the progeny is expected to be bbSs, expressing  blistery wings and normal bristles

     4/16 = 1/4 = 25% of the progeny is expected to be bbss, expressing  blistery wings and spineless bristles    

5 0
3 years ago
Janet installed a dimmer on the lights in her bedroom. She slid the dimmer switch, causing the resistance in the circuit to
Anton [14]

Answer: The correct answers are option(b) and(d).

Explanation:

When the lamp was dimmer  the resistance offered by the lamp was more which just resist the flow current from the circuit.

V=RI (Ohm's Law)

When the Janet decrease the resistance to (R') by sliding the dimmer switch (voltage remained constant). On decreasing the resistance the flow of current in circuit will increase by which light of the lamp will become brighter.

Hence, from the enlisted options the correct options option(b) and(d).

4 0
3 years ago
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I need help on this one??
Luba_88 [7]

Answer:

A

Explanation:

It's basically doing by its own

6 0
2 years ago
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