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3 years ago

14

PLEASE PLEAE PLEASE HELP

1 answer:

scoundrel [369]3 years ago

7 0

She bought 4 coffees! :)

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Two numbers have theses properties . both numbers are greater than 6 . their hcf = 6 . their lcm = 60. what are the two numbers

aleksandrvk [35]

Let the numbers be x and y.
x*y=HCF*LCM=6*60=360
thus
y=360/x
next we find the list of combinations of x and y and test if they satisfy the conditions above:
(6,60),(12,30),(18,20),(24,15)
out of the above, only (6,60) and (12,30) satisfy both conditions. Thus our answer is:
(6,60) or (12,30)

6 0

3 years ago

What is the skipping sequence of 90,92,__,__,99,__

DaniilM [7]

that is not possible cause the first 2 indicate that the pattern is counting by 2s

5 0

3 years ago

The power of ten representation of four thousandths

m_a_m_a [10]

Answer:

if its thousandths, its 4 x 10^-1. If you mean 4000, its 4 x 10^3

Step-by-step explanation:

5 0

3 years ago

Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)

Likurg_2 [28]

Answer:

$d = 14$

$(-2,-1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

Substitute: $d = \sqrt{(-9-5)^2+(-1-(-1))^2}$
Simplify: $d = \sqrt{(-9-5)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-14)^2+(0)^2}$
Evaluate: $d = \sqrt{196}$
Evaluate: $d = \14$

<u>Step 3: Find Midpoint</u>

Substitute: $(\frac{5-9}{2},\frac{-1-1}{2})$
Subtract: $(\frac{-4}{2},\frac{-2}{2})$
Divide: $(-2,-1)$

7 0

3 years ago

A function has x-intercept 3 and y-intercept 2. Which of the functions below could be this function?

Sergeeva-Olga [200]

we are given

x-intercept is 3

so,

a=3

y-intercept is 2

b=2

now, we can intercept formula of line

$\frac{x}{a} +\frac{y}{b}=1$

now, we can plug

a=3 and b=2

$\frac{x}{3} +\frac{y}{2}=1$

now, we will get rid of denominators

so, we can multiply both sides by 6

$6*\frac{x}{3} +6*\frac{y}{2}=6*1$

$2x +3y=6$

we can also write it as

$3y-6=-2x$

so, option-D..................Answer

3 0

3 years ago