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alexandr402 [8]
3 years ago
15

H/5-h(k+j) use h=5, j=3, and k=7​

Mathematics
2 answers:
Goryan [66]3 years ago
7 0

\text{h}=5 \ \text{and} \ \text{j}=3 \ \text{and} \ \text{k}=7\\\\\frac{\text{h}}{5}-\text{h}(\text{k}+\text{j})=\frac{5}{5}-5\cdot(3+7)=1-5\cdot10=1-50=\boxed{-49}

mariarad [96]3 years ago
3 0

h/5 - h(k + j) => 5/5 - 5(7 + 3)

5/5 - 5(7 + 3)

1 - 5 × 10

1 - 50 = -49

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