Answer:
c. x=50; m< LOK = 114
Step-by-step explanation:
(x+64) + 66 = 180
x + 130 = 180
x = 50
We have to put the numbers in order..
(121,122,125, 126,132),M,(135,136,136,138,140)
minimum : (smallest number) = 121
Q1 : 125
Q2 (median) : (132 + 135) / 2 = 267/2 = 133.5
Q3 : 136
maximum : (largest number) = 140
There's a quick, easy, sloppy way, and there's a good math way.
Here's the good math way:
If the integers are consecutive, then you can call them 'x', (x+1), and (x+2).
We know what their sum is, so let's add them up:
x + (x+1) + (x+2) = 336
x + x+1 + x+2 = 336
Combine the terms that are alike on the left side:
3x + 3 = 336
Subtract 3 from each side: 3x = 333
Divide each side by 3 : <u> x = 111</u>
The integers are<em> 111, 112, </em>and<em> 113</em> .
