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sweet-ann [11.9K]
2 years ago
7

A candy company puts 9 gumdrops in each bag. How many gumdrops will the company need to fill 21 bags?

Mathematics
1 answer:
vodomira [7]2 years ago
8 0

Answer:

189 gumdrops

Step-by-step explanation:

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Imagine that you are representing your classmates. What are their needs? What would you advocate for their behalf? Not math rela
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As a former runner upper Senior Class Secretary I can say that your classmates need the following:

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In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will e
Olenka [21]

Answer:

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Flagged as future criminal

Event B: Commits a crime.

In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will eventually commit a crime.

This means that P(B) = \frac{100}{1000100} = 0.00009999

If a person is going to commit a crime, the Precogs identify that person correctly 99.999% of the time

This means that P(A|B) = 0.99999

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0.99999 out of 0.00009999(identified and commits crime).

(1-0.99999) out of (1-0.00009999) (identifed and does not commits crime). So

P(A) = 0.99999*0.00009999 + (1-0.99999)*(1-0.00009999) = 0.000109988

What is the probability that a person flagged as a future criminal by the Precogs will actually commit a crime

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.00009999*0.99999}{0.000109988} = 0.9091

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

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2 years ago
What two ordered pairs will show both intercepts for y=6x-5
podryga [215]

The equation is y=6x-5

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