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marishachu [46]
2 years ago
5

Simplify the expression and write the result in standard form, a+bi. Write all numbers as integers or simplified fractions.

Mathematics
2 answers:
andrey2020 [161]2 years ago
8 0

Step-by-step explanation:

- 14 +   \sqrt{ \frac{ - 125}{10} }  \\  - 14 +  \frac{5 \sqrt{5} i}{ \sqrt{10} }  \\  =  - 14 +  \frac{5i}{ \sqrt{2} }  \\  =  - 14 +  \frac{5i \sqrt{2} }{ \sqrt{2} \times  \sqrt{2}  }  \\  - 12 +  \frac{5 \sqrt{2}i }{2}  \\ thank \: you

Marianna [84]2 years ago
4 0

Answer:

- 14 +  \sqrt{ \frac{ - 5 \times 5 \times 5}{10} }

- 14 + 5 \sqrt{ \frac{ - 1}{2} }

- 14 +  \frac{5 \sqrt{ - 1} }{ \sqrt{2} }

- 14 +  \frac{5i}{ \sqrt{2} }

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The difference quotient for the function f(x) is h+2x-7

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Difference quotient formula

\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}

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find the difference quotient using the formula

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replace x with x+h

f(x) = x^2 - 7x + 8 \\f(x+h)=\mathrm{ }\left(x+h\right)^2-7\left(x+h\right)+8\\Expand \; and \; simplify\\f(x+h)=x^2+2xh+h^2-7\left(x+h\right)+8\\f(x+h)=x^2+2xh+h^2-7x-7h+8

Now replace it in our formula and also replace f(x)

\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}\\ \frac{x^2+2xh+h^2-7x-7h+8-(x^2 - 7x + 8)}{h} \\\frac{x^2+2xh+h^2-7x-7h+8-x^2 + 7x - 8}{h} \\\\\frac{h^2+2xh-7h}{h}\\factor \; out \; h\\\frac{h\left(h+2x-7\right)}{h}\\h+2x-7

Learn more :brainly.com/question/23630564

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How is the graph of y = 3x^2 + 7 different from the graph of y = 3x^2?
Lana71 [14]
The 1st one is not linear but the second one is.
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3 years ago
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